我的文件里面有20k + IP:
104.20.15.220,104.20.61.219,104.20.62.219,104.20.73.221,104.20.74.221,104.20.14.220
104.20.15.220,104.20.73.221,104.20.74.221,104.25.195.107,104.25.196.107,104.20.14.220
91.215.154.209
...
问题是如何在每个字符串上拆分成单个IP:
104.20.15.220
104.20.61.219
答案 0 :(得分:10)
只需使用以下任一命令替换带有新行的逗号:
tr ',' '\n' < file
sed 's/,/\n/g' file
perl 's/,/\n/g' file
awk 'gsub(/,/,"\n")' file
...或匹配每个文本块,直到逗号或行尾:
grep -oP '.*?(?=,|$)' file
...或循环浏览字段并打印出来:
awk -F, '{for(i=1;i<=NF;i++) print $i}' file
...或者将记录分隔符设置为逗号,让awk
完成所有工作:
awk -v RS=, '1' file
awk 1 RS=, file
...或匹配IP,您可以使用Matching IPv4 Addresses中的正则表达式:
grep -oE '((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)' file
他们都回来了:
104.20.15.220
104.20.61.219
104.20.62.219
104.20.73.221
...
答案 1 :(得分:2)
这会将所有命令转换为换行符。
tr ',' '\n' <filename
或
awk 'BEGIN{FS=",";OFS="\n"}{$1=$1}1' filename