Question

下面的代码显示了每小时的预约次数和“没有预约”＃39;如果没有预约。

我想连续分组＆＃39;没有预约＆＃39;根据时间插槽

例如，当前代码的输出是 -

# plotting all the file data and saving the plots import os import csv import matplotlib.pyplot as plt def graphWriterIRIandRut(): m = 0 List1 = [] List2 = [] List3 = [] List4 = [] fileList = [] for file in os.listdir(os.getcwd()): fileList.append(file) while m < len(fileList): for col in csv.DictReader(open(fileList[m],'rU')): List1.append(col['x1']) List2.append(col['y1']) List3.append(col['x2']) List4.append(col['y2']) plt.subplot(2, 1, 1) plt.grid(True) # colors = np.random.rand(2) plt.plot(List1,List2,c=colors) plt.tick_params(axis='both', which='major', labelsize=8) plt.subplot(2, 1, 2) plt.grid(True) # colors = np.random.rand(2) plt.plot(List1,List3,c=colors) plt.tick_params(axis='both', which='major', labelsize=8) m = m + 1 continue plt.show() plt.gcf().clear() plt.close('all')

我希望输出为

10:00 AM to 11:00 AM -> No Appointment 11:00 AM to 12:00 PM -> No Appointment 12:00 PM to 01:00 PM -> No Appointment

代码如下： -

10:00 AM to 01:00 PM -> No Appointment

Answer 1

首先，可以准备阵列：

@time_group = ['6:00:00','7:00:00', ...]
@stacked = @time_group.each_with_object([]) do |start, memo|
  range = Time.parse(start)..Time.parse(start)+3600
  booked = Appointment.where(start_time: range)
  if memo.empty? || !booked.empty? || !memo.last.last.empty?
    memo << [range, booked] # no sequenced empty slots
  else
    memo << [memo.pop.begin..range.end, booked] # merge ranges
  end
end.to_h # { ranges => booked }

现在让我们输出它们：

<% @stacked.each do |range, booked| %>
  .....
<% end %>

Answer 2

试试这个

<% @time_group = ['6:00:00','7:00:00','8:00:00','9:00:00','10:00:00','11:00:00','12:00:00','13:00:00','14:00:00','15:00:00','16:00:00','17:00:00','18:00:00','19:00:00','20:00:00','21:00:00','22:00:00','23:00:00'] %>

#Loop through each hour in @time_group
<% @time_group.each_with_index do |t,index| %>
  <% t1 = Time.parse(t) %>
  <% t2 = Time.parse(t) + 3600 %>
  <% @booked = Appointment.where(start_time: t1..t2) %>


  #It will holds the No Appointment Timings into it
  no_appointment_array = []

  #if appointment is available show appointment else show no appointment
  <% if @booked.size > 0 %>

    #Calling the Function
    display_no_appointment(no_appointment_array) if not no_appointment_array.empty?


    #Show time interval e.g 1:00 PM to 2:00 PM
    <%= Time.parse(t).strftime('%I:%M %p') %> to <%= (Time.parse(t) + 3600).strftime('%I:%M %p') %>

    <% @booked.each do |app| %>
      <%= app.start_time.strftime('%I:%M') %>  
    <% end %>

  <% else %>  

   no_appointment_array << [Time.parse(t).strftime('%I:%M %p'), (Time.parse(t) + 3600).strftime('%I:%M %p')]

  <% end %>
<% end %>


def display_no_appointment(no_appointment_array)
  puts "#{no_appointment_array.first[0]} to #{no_appointment_array.last[1]} -> No Appointment"

  #It Clears all Previous No Appointment
  no_appointment_array.clear

end

Answer 3

首先，我建议你使用'@ booked.present？'而不是'if @ booked.size＆gt; 0'

你尝试过这样的事吗？我没有测试过这段代码，这对于一个可能的解决方案几乎是一个想法。希望它对你有所帮助。

<% no_appointment_starts_at = nil %>
<% no_appointment_ends_at = nil %>

<% @time_group.each_with_index do |t,index| %>
    <% t1 = Time.parse(t) %>
    <% t2 = Time.parse(t) + 3600 %>
    <% @booked = Appointment.where(start_time: t1..t2 %>

    #Show time interval e.g 1:00 PM to 2:00 PM


    #if appointment is available show appointment else show no appointment
    <% if @booked.present? %>

    <% @booked.each do |app| %>
        <% unless no_appointment_ends_at.blank? %>
            <%= Time.parse(no_appointment_starts_at).strftime('%I:%M %p') %> to <%= (Time.parse(no_appointment_ends_at) + 3600).strftime('%I:%M %p') %>
            <% no_appointment_ends_at = nil%>
        <% end %>
        <%= Time.parse(t).strftime('%I:%M %p') %> to <%= (Time.parse(t) + 3600).strftime('%I:%M %p') %>
      <%#= app.start_time.strftime('%I:%M') %>
        <% no_appointment_starts_at = t2 %>  
    <% end %>

    <% else %>  
      <% last_appointment_ends_at = t2  %>
    <% end %>
<% end %>

没有预约的团体

3 个答案: