从下面的表A中,我想从列Color和中拆分值 用它生成新行。我想要的结果显示在表结果中 下方。
表A
Animal | Gender | Color -------|--------|--------------------- Cat | Male | White, Black, Brown Cat | Female | White Dog | Male | Black, Yellow Dog | Female | Black
表格结果
Animal | Gender | Color -------|--------|--------------------- Cat | Male | White Cat | Male | Black Cat | Male | Brown Cat | Female | White Dog | Male | Black Dog | Male | Yellow Dog | Female | Black
我如何使用SQLite实现这一目标,还是有任何其他建议?
答案 0 :(得分:2)
假设您正在将每条记录作为字符串获取,如下所述,您可以从中分割所有数据,如下所示:
创建一个包含动物,颜色和性别等属性的类,如下所示
class AnimalData // You can give any name
{
String strAnimal, strGender, strColor;
public AnimalData(String strAnimal, String strGender, String strColor)
{
this.strAnimal = strAnimal;
this.strGender = strGender;
this.strColor = strColor;
}
public String getStrAnimal()
{
return strAnimal;
}
public String getStrGender()
{
return strGender;
}
public String getStrColor()
{
return strColor;
}
}
现在我正在使用3个静态变量,其中包含您从数据库获得的数据,您需要使用它们而不是以下变量
String strAnimalData[] = {"Cat","Cat","Dog","Dog"};
String strGenderData[] = {"Male","Female","Male","Female"};
String strColorData[] = {"White,Black,Brown","White","Black,Yellow","Black"};
现在我正在使用一种方法,它会从上面的值中给出结果列表
public List<AnimalData> getAllAnimalData()
{
List<AnimalData> strAllAnimalData = new ArrayList<>();
for(int i = 0; i < strAnimalData.length; i++)
{
if(strAnimalData[i].indexOf(",") > 0)
{
String strSubAnimalData[] = strAnimalData[i].split(",");
for(int j = 0; j < strSubAnimalData.length; j++)
{
AnimalData ad = new AnimalData(strSubAnimalData[j], strGenderData[i], strColorData[i]);
strAllAnimalData.add(ad);
}
}
else if(strGenderData[i].indexOf(",") > 0)
{
String strSubGenderData[] = strGenderData[i].split(",");
for(int j = 0; j < strSubGenderData.length; j++)
{
AnimalData ad = new AnimalData(strAnimalData[i], strSubGenderData[j], strColorData[i]);
strAllAnimalData.add(ad);
}
}
else if(strColorData[i].indexOf(",") > 0)
{
String strSubColorData[] = strColorData[i].split(",");
for(int j = 0; j < strSubColorData.length; j++)
{
AnimalData ad = new AnimalData(strAnimalData[i], strGenderData[i], strSubColorData[j]);
strAllAnimalData.add(ad);
}
}
else
{
AnimalData ad = new AnimalData(strAnimalData[i], strGenderData[i], strColorData[i]);
strAllAnimalData.add(ad);
}
}
// Below code is just for Display Data
for(AnimalData tempData: strAllAnimalData)
{
System.out.println("\t" + tempData.getStrAnimal() + "\t" + tempData.getStrGender() + "\t" + tempData.getStrColor());
System.out.println("\n");
}
}
注意: - 目前,当每个位置只有一个变量有更多数据时,这将起作用,例如,如果动物在位置1处有“Cat,Dog”而Color在位置上也有“红色,棕色” 1然后它只会将动物与颜色分开,因为你需要在循环中实现相同的逻辑。