Question

我正在尝试使用下面的代码获取滑动的位置，但无论我在屏幕上滑动的位置，它都会返回相同的位置。

CODE：

-(void) recognizeTapGesture : (UITapGestureRecognizer*)sender  {

    CGPoint event;
    event = [sender locationInView: nil ];

    NSLog(@"Tap Detected (%f,%f) %lu",event.x,event.y,(unsigned long)sender.numberOfTouches);
} 

-(void) recognizeLeftSwipeGesture : (UISwipeGestureRecognizer*)sender  {

    CGPoint event;
    event = [sender locationInView: nil ];

    NSLog(@"Left Swipe Detected (%f,%f) %lu",event.x,event.y,(unsigned long)sender.numberOfTouches);

}

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {

    _TapGesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(recognizeTapGesture:)];

    _LeftswipeGesture = [[UISwipeGestureRecognizer alloc] initWithTarget: self action:@selector(recognizeLeftSwipeGesture:) ];

    _LeftswipeGesture.direction = UISwipeGestureRecognizerDirectionLeft;

    _LeftswipeGesture.cancelsTouchesInView = NO;

    _TapGesture.cancelsTouchesInView = NO;

    [[self window] addGestureRecognizer:_LeftswipeGesture];

    [[self window] addGestureRecognizer:_TapGesture];

    return YES;
}

输出：

Tap Detected (286.500000,460.500000) 1
Left Swipe Detected (0.000000,0.000000) 1

此代码是否足够，以找到滑动的位置。我想知道如何在objective-c中找到滑动的位置。有什么我想念的吗？为什么触摸次数始终为1.当我设置所需的最小触摸次数时，不会检测到滑动。

Answer 1

我不知道为什么会出现这种情况，但tapGesture会在窗口级获取位置，而swipeGesture会从View级别获取位置。因此，在swipeGesture的情况下，位置检索功能变为此

event = [sender locationInView: currentviewController.view ];

要获取currentviewcontroller，我们可以创建函数来获取它并使用上面的代码，或者只是在UIViewController中定义函数和gesturerecognizer并使用它，

event = [sender locationInView: self.view ];

如何获得滑动手势的位置

1 个答案: