Question

我有以下表员工（emp_id，name，salary，manager_id）我想编写查询以检索manager_id和由该经理管理的所有员工工资的总和，或者甚至由该经理管理的经理管理。我写了这样的查询：

Select manager_id , sum(salary) 
from employees 
connect by prior emp_id = manager_id
  start manager_id = 100 
group by manager_id;

但是我没有按照自己的意愿检索薪金。

Answer 1

构建层次结构首先记住ROOT，然后按root分组。例如。 emp_id = 100的经理的薪水以及他/她经理的所有员工：

SELECT manager_id, SUM(salary) "Total_Salary" 
FROM (
   SELECT CONNECT_BY_ROOT emp_id as manager_id, Salary
   FROM emploees
   START WITH emp_id=100
   CONNECT BY PRIOR emp_id = manager_id )
GROUP BY manager_id
ORDER BY manager_id;

Answer 2

@ Serg的解决方案很好，但对于一位经理来说，即使是更简单的查询也可以：

select 21 as id, sum(salary) as summed
  from employees e
  start with emp_id = 21
  connect by prior emp_id = manager_id;

如果您不想要经理的薪水，请添加where level<>1。

测试数据：

create table employees(emp_id number(4), name varchar2(10), 
                       salary number(6), manager_id number(4));

insert into employees values (   1, 'King',   10000, null);
insert into employees values (  11, 'Smith',   8000,    1);
insert into employees values (  21, 'Jones',   9000,    1);
insert into employees values ( 211, 'Brown',   7500,   21);
insert into employees values ( 212, 'Adams',   6200,   21);
insert into employees values (2111, 'White',   5000,  211);

输出：

    ID     SUMMED
------ ----------
    21      27700

具有分层查询的组功能

2 个答案: