Question

我有下表备份，它结合了小时，人员，备份类型和备份日期的数据：

data        |   type   |   persons   |  hours
==============================================
2015-06-12      15           4            8
2015-06-12      15           4            8
2015-06-12      15           4            8
2015-06-12      15           4            8
2015-06-13      14           2            4
2015-06-13      14           2            4

我试图编写一个返回以下结果的查询：

       data     |   type   |   persons   |  hours
    ==============================================
    2015-06-12      15           4            32
    2015-06-13      14           2            8

我的查询如下：

SELECT "data", "type", SUM("hours"), "persons" FROM "backup" GROUP BY "type", "data", "persons" ORDER BY "data"

但它确实按我想要的方式工作:(

修改

使用此查询后

：

SELECT "data", "type", "persons", SUM("hours") AS "hours" FROM "backup" WHERE "project" = '2000030' GROUP BY "type", "data", "persons" ORDER BY "data"

SQL返回此数据：

   data    |   type  |  persons  |  hours
==========================================
2011-12-16 | 2003774 |     9     |   12
2011-12-16 | 2003774 |    10     |   12

但应该有：

   data    |   type  |  persons  |  hours
==========================================
2011-12-16 | 2003774 |     9     |   54

在DB中我有9条记录（每人一条记录），每个人的单元格为9，每小时单元格为9.我需要将每个日期和每种类型的备份（支持）的小时数相加。

Answer 1

正确的查询是

SELECT "data", "type", "persons", SUM("hours") FROM "backup" GROUP BY "type", "data", "persons" ORDER BY "data"

＆＃34;人＆＃34;和SUM（＆＃34;小时＆＃34;）被切换。根据预期结果，这是唯一的问题。

更新：如果您希望每种类型有一行，请尝试以下操作：

SELECT "data", "type", MAX("persons"), SUM("hours") FROM "backup" GROUP BY "type", "data" ORDER BY "data"

使用SUM和GROUP进行SQL查询

1 个答案: