Question

Angular2 rc.6

在json数据上运行循环时出现以下错误

core.umd.js：5995 EXCEPTION：app / modules / mbs / components / menu.html：5：4引起的错误：无法找到'object'类型的不同支持对象'[object Object]'。 NgFor仅支持绑定到Iterables，例如Arrays。

我的html循环，注意：我只是想在响应中迭代属性和数组。

<li *ngFor="let item of menuItems">
{{item}}
</li>

我的服务方法

getMenuItems():Promise<any>{
    return this.http.get('api/menu').toPromise().
    then(response => response.json())
        .catch(this.handleError)

}

以下是我的json回复

{ "text": "Menu", "children": [ { "text": "Home", "url": "/spatt-web/home" }, { "text": "Configure", "children": [ { "text": "Tri-Party Program", "children": [ { "text": "Margins and Filters", "url": "/sp-rrp/config/operation" }, { "text": "Fields and Desirability", "url": "/spatt-rrp/config/program" } ] }, { "text": "Shared Settings", "url": "/shared-config/config" }, { "text": "SOMA Limits", "url": "/outright-config/config" } ] }, { "text": "Plan", "children": [ { "text": "Tri-Party RRP Operations", "url": "/spatt-rrp/plan" } ] }, { "text": "Track" }, { "text": "Administer" }, { "text": "Help", "children": [ { "text": "RRP Operations", "url": "RRPference" }, { "text": "RRP Margin Calls and Recalls", "url": "RRPRecallference" } ] } ] }

Answer 1

看起来你想要

<li *ngFor="let item of menuItems.children">
{{item}}
</li>

Answer 2

通常来说，该错误表示您正在尝试迭代对象，而不是数组或可观察对象。

Answer 3

如果您要遍历对象：

  <div *ngFor="let location of locations | keyvalue">
       {{location.key}} - {{location.value | json}}
  </div>

KeyValuePipe Documntation

angular2 NgFor仅支持绑定到诸如Arrays之类的Iterables

3 个答案: