Question

我的意思是，这是我的代码：

// Create the web request (posts/1)
HttpWebRequest request = WebRequest.Create("https://jsonplaceholder.typicode.com/posts/1") as HttpWebRequest;
// Get response  
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
   // Get the response stream  
   StreamReader reader = new StreamReader(response.GetResponseStream());

   {
       string myString = reader.ReadToEnd();
       System.IO.File.WriteAllText(@"C:\Users\admin\Documents\Visual Studio 2015\Projects\WriteText.json", myString);
   }


   // JSON deserialize from a file
   String JSONstring = File.ReadAllText(@"C:\Users\admin\Documents\Visual Studio 2015\Projects\WriteText.json");
   //  List<PARSE> pList = JsonConvert.DeserializeObject<List<PARSE>>(JSONstring);
   PARSE pList = JsonConvert.DeserializeObject<PARSE>(JSONstring);

如何在不保存流并再次将其加载到字符串的情况下执行此操作。我想直接将我的流用于String＆＃39; JSONstring＆＃39;然后解析它。

Answer 1

这是一个如何将HTTP流解析为Json（没有错误处理）的示例。玩它并告诉我们您是否遇到任何具体问题。在这段代码中。 API_Json是带有反序列化类的类，我正在反序列化API_Json.RootObject：

   public async Task<API_Json.RootObject> walMart_Lookup(string url)
    {
        lookupIsWorking = true;
        HttpClientHandler handler = new HttpClientHandler()
        {
            AutomaticDecompression = DecompressionMethods.GZip | DecompressionMethods.Deflate
        };
        using (HttpClient http = new HttpClient(handler))
        {

            http.DefaultRequestHeaders.AcceptEncoding.Add(new System.Net.Http.Headers.StringWithQualityHeaderValue("gzip"));
            http.Timeout = TimeSpan.FromMilliseconds(Timeout.Infinite);
            url = String.Format(url);
            using (var response = await http.GetAsync(url, HttpCompletionOption.ResponseHeadersRead))
            {
                Console.WriteLine(response);
                var serializer = new JsonSerializer();

                using (StreamReader sr = new StreamReader(await response.Content.ReadAsStreamAsync()))
                {
                    using (var jsonTextReader = new JsonTextReader(sr))
                    {
                        var root = serializer.Deserialize<API_Json.RootObject>(jsonTextReader);
                       lookupIsWorking = false;
                        return root;

                    }
                }

                //var obj = (API_Json_Special_Feeds.RootObject)serializer.Deserialize(sr, typeof(API_Json_Special_Feeds.RootObject));
                //return obj;
            }

        }


    }

Answer 2

您的代码包含解决方案

// Create the web request (posts/1)
HttpWebRequest request = WebRequest.Create("https://jsonplaceholder.typicode.com/posts/1") as HttpWebRequest;
// Get response  
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
   // Get the response stream  
   StreamReader reader = new StreamReader(response.GetResponseStream());

   {
       //string myString = reader.ReadToEnd();
       //System.IO.File.WriteAllText(@"C:\Users\admin\Documents\Visual Studio 2015\Projects\WriteText.json", myString);
   }


   // JSON deserialize from a file
   // String JSONstring = File.ReadAllText(@"C:\Users\admin\Documents\Visual Studio 2015\Projects\WriteText.json");
   //  List<PARSE> pList = JsonConvert.DeserializeObject<List<PARSE>>(JSONstring);
   PARSE pList = JsonConvert.DeserializeObject<PARSE>(reader.ReadToEnd());

   reader.close();

直接使用流进行解析而不是保存文件

2 个答案: