Question

我有一个数据对象如下：

[{"type":"Positive","value":14.71},{"type":"Neutral","value":50.0},{"type":"Negative","value":35.29}]

我想将其更改为以下指定的格式：

{
"refno": "",
"ddesc": "",
"free": "0",
"fgift": "",
"sgift": "",
"sandage": {
               "bank": "",
                "bag": ""
           },
"inst": "",
"items": [{
             "itemid": "606",
             "qty": "1",
    "sub": [{
        "item": "1586",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }, {
        "item": "1588",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }, {
        "item": "1589",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }, {
        "item": "1590",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }]
}, {
    "itemid": "639",
    "qty": "1",
    "sub": [{
        "item": "1618",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }, {
        "item": "1612",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }, {
        "item": "1611",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }, {
        "item": "1610",
        "qty": "1",
        "type": "addon",
        "ext": ""
    }]
}],
"discount": "0",
"coupon": [],
"delivery": "",
"user": {
    "id": "13",
    "fname": "Demo",
    "lname": "Order",
    "phone": "9876543210",
    "dno": "",
    "add1": "",
    "add2": "",
    "postcode": "",
    "username": "demo@theepos.com",
    "status": "1"
},
"otype": "1",
"ptype": "0",
"app_id": "A1A2A3A4", 
 "app_key": "K1K2K3K4",                   
"request": "placeorder"
}

Answer 1

使用 Object.keys 和 Array#map 方法。

＆＃13;

var data = [{
  "Positive": "14.71",
  "Neutral": "50.0",
  "Negative": "35.29"
}];

var res = Object.keys(data[0]) // get all object property names
  // iterate over property names array
  .map(function(k) {
    // generate array element using property value
    return {
      type: k,
      // cast data value to number using plus-sign prefix(as per requirement)
      value: +data[0][k]
    }
  })

console.log(res);

＆＃13;

Answer 2

我使用通用的has no exported mng 'provideRouter' has no exported mng 'RouterConfig' has no exported mng 'ROUTER_DIRECTIVES' has no exported mng 'addProviders'函数解决了这个问题，这对您在JavaScript中尝试pairs，map或reduce个对象非常有用

filter

或者，let input = [{"Positive":"14.71","Neutral":"50.0","Negative":"35.29"}]; let pairs = o => Object.keys(o).reduce((acc,k) => [...acc, [k, o[k]]], []); let output = pairs(input[0]).map(([type,value]) => ({type, value: Number(value)})); console.log(output);可以作为生成器实现，这将产生整体更可读的结果

pairs

let input = [{"Positive":"14.71","Neutral":"50.0","Negative":"35.29"}]; function* pairs(o) { for (let k of Object.keys(o)) yield [k, o[k]]; } let output = Array.from(pairs(input[0]), ([type, value]) => { return {type, value: Number(value)}; }); console.log(output);提供了一种从可迭代值（以及可选 map ）中收集值的便捷方法，但您不必使用它，如果你不想。在熟悉它之前，您可以轻松地使用Array.from循环将键/值对收集到输出对象中。

for-of

更改JavaScript Data对象的格式

2 个答案: