Cakephp仅与params相关联

Question

我需要创建一个自定义网址，例如http://example.com/type_of_institution/institutin_name

我在/routes.php中添加了以下几行

$routes->connect(
    '/:type/:name',
    ['controller' => 'Institutions', 'action' => 'view'],
    ['type' => '[a-z_]+', 'name' => '[a-z_]+', 'pass' => ['type','name']]
);

//in my controller
public function view($type,$name){
   this->autoRender = false;
}

我已尝试使用http://example.com/private_institution/test_institution，但我收到以下错误：

Error: [Cake\Routing\Exception\MissingControllerException] Controller class PrivateInstitution could not be found.

我改成

之后

$routes->connect(
        'institutions/:type/:name',
        ['controller' => 'Institutions', 'action' => 'view'],
        ['type' => '[a-z_]+', 'name' => '[a-z_]+', 'pass' => ['type','name']]
    );

与http://example.com/institutions/private_institution/test_institution

合作

在Cakephp 3中，只有params制作一个url？（第一个例子）