Question

CREATE OR REPLACE FUNCTION public.get_locations(
    location_word varchar(50)
    ) 
RETURNS TABLE
(
    country varchar(50),
    city varchar(50)
)
AS $$
DECLARE
location_word_ varchar(50);
BEGIN
location_word_:=concat(location_word, '%');
RETURN QUERY EXECUTE format('   (SELECT c.country, ''::varchar(50) as city FROM webuser.country c 
                                    WHERE lower(c.country)  LIKE %L  LIMIT 1)
                                UNION
                                (SELECT c.country,ci.city FROM webuser.country c
                                    JOIN webuser.city ci ON c.country_id=ci.country_id
                                    WHERE lower(ci.city) LIKE %L LIMIT 4)', 
                                    location_word_,
                                    location_word_ )    ;

END
$$ language PLPGSQL STABLE;

这是我得到的错误;

错误：语法错误在或接近＆＃34;％＆＃34;
第2行：在哪里更低（c.country）LIKE＆＃39; a％＆＃39;限制1）

为什么我会收到此错误？

修改

当我刚用''::varchar(50)取代''''::varchar(50)时，它就有效了！

Answer 1

尝试下一个更正的功能：

CREATE OR REPLACE FUNCTION public.get_locations(
    location_word varchar(50)
    ) 
RETURNS TABLE
(
    country varchar(50),
    city varchar(50)
)
AS $$
DECLARE
location_word_ varchar(50);
BEGIN
location_word_:=concat(location_word, '%');
RETURN QUERY EXECUTE format('   (SELECT c.country, ''''::varchar(50) as city FROM webuser.country c 
                                    WHERE c.country ILIKE ''%L'' LIMIT 1)
                                UNION
                                (SELECT c.country,ci.city FROM webuser.country c
                                    JOIN webuser.city ci ON c.country_id=ci.country_id
                                    WHERE ci.city ILIKE ''%L'' LIMIT 4)', 
                                    location_word_,
                                    location_word_ )    ;

END
$$ language PLPGSQL STABLE;

使用Union子句postgresql 9.5

1 个答案: