Question

我正在努力探索Relay路线，反应路由器参数以及构建查询和容器一般非常困难！

我想在用户点击FeatureList中的特定功能时编辑功能。它传递了一个名为＆＃34; id＆＃34;这是Route.js中的功能的ID

  <Route path='/' component={AppComponent} queries={ViewerQuery}>
    <IndexRoute component={FeaturesContainer} queries={ViewerQuery} />
    <Route path='/feature' component={FeatureComponent} queries={ViewerQuery} />
    <Route path="/feature/edit/:id" component={FeatureEditComponent} queries={FeatureQuery}/>
    <Redirect from='*' to='/' />
  </Route>

在我的FeatureQuery文件中，我有以下查询：

export default {
  viewer: (Component) => Relay.QL`
    query {
      viewer {
        ${Component.getFragment('viewer')}
      }
    }
  `
};

此时我完全卡住了。如何扩展它以包含＆＃34; id＆＃34;并使用＆＃34; id＆＃34;来查询功能？相关的继电器容器片段的形状是什么样的？我只看到一个深层次的例子。

我试过了，但我知道它不对：

export default {
    feature: (Component) => Relay.QL`
        query {
            viewer {
                features(id:$id) {
                  ${Component.getFragment('feature')}
                }
            }
        }
    `
};

这是获取功能列表的当前中继容器，如何通过id返回1功能？：

export default Relay.createContainer(CreativeEditComponent, {
  fragments: {
    viewer: () => Relay.QL`
        fragment on User {
        id,
        features(first: 20) {
          edges {
            node {
              id
              name
              description

            }
          }
        }
      }`
  }
});

我在GraphiQL中测试了一个查询，它按预期工作：

query {
  viewer {
    features(id:"1") {
      edges {
        node {
          id
          name
          description
        } 
      }
    } 
  }
}

结果：

{
  "data": {
    "viewer": {
      "features": {
        "edges": [
          {
            "node": {
              "id": "Q3JlYXRpdmU6MQ==",
              "name": "React",
              "description": "A JavaScript library for building user interfaces."
            }
          }
        ]
      }
    }
  }
}

schema.js：

const userType = new GraphQLObjectType({
  name: 'User',
  description: 'A person who uses our app',
  fields: () => ({
    id: globalIdField('User'),

    features: {
      type: featureConnection,
      description: 'Features that I have',
      //args: connectionArgs,

      args: {
        id: {
          type: GraphQLString,
        },
        after: {
          type: GraphQLString,
        },
        first: {
          type: GraphQLInt,
        },
        before: {
          type: GraphQLString,
        },
        last: {
          type: GraphQLInt,
        },
      },

      resolve: (_, args) => {
        return resolveGetFeatures(args)
      },
    },


  }),
  interfaces: [nodeInterface]
});



const featureType = new GraphQLObjectType({
  name: 'Feature',
  description: 'Feature integrated in our starter kit',
  fields: () => ({
    id: globalIdField('Feature'),
    name: {
      type: GraphQLString,
      description: 'Name of the feature'
    },
    description: {
      type: GraphQLString,
      description: 'Description of the feature'
    }
  }),
  interfaces: [nodeInterface]
});

Answer 1

您需要将路由器变量传递给您的片段。

const ViewerQuery = {
  viewer: (Component, vars) => Relay.QL`
    query {
      viewer {
        ${Component.getFragment('viewer', vars)} # <-- this
      }
    }
  `
}

我从此处复制了此代码详细信息：https://github.com/relay-tools/react-router-relay/issues/92#issuecomment-235641397

然后您可以在组件中使用id变量，但是您需要id的初始值：

export default Relay.createContainer(CreativeEditComponent, {
  initialVariables: {
    id: ''
  },
  fragments: {
    viewer: () => Relay.QL`
        fragment on User {
          id,
          feature(id:$id) {
            id
            name
            description
          }
        }`
    }
});

在schema.js中为您的用户类型定义一个字段，该字段仅提供一个功能：

const userType = new GraphQLObjectType({
  name: 'User',
  description: 'A person who uses our app',
  fields: () => ({
    id: globalIdField('User'),
    feature: {
      type: featureType,
      description: 'feature',
      args: {
        id: {
          type: GraphQLString,
          description: 'The id of the feature'
        }
      },
      resolve: (_, args) => resolveGetFeature (args),
    },
    ...

如何使用Relay容器，react-router和GraphQL按id获取和显示项目

1 个答案: