我有一个问题在过去几个小时让我疯了。
我在R中使用以下软件包:forecast
,fracdiff
,doParallel
,foreach
等。我也有以下功能。
doparPredictions <- function(train, test, cl){
training = train
pred = foreach (i = 1:length(test), .combine=c) %dopar% {
if (i > 1) {
training = c(train,test[1:i-1])
}
fit = nnetar(training, 8, P=1, 5)
forecast(fit, 1)$mean
}
}
...以及以上功能WORKS!
但是,如果我用nnetar(training, 8, P=1, 5)
替换fracdiff(training, 3, 1, h=0.00001)
,则函数会因以下错误而失败。
Error in { : task 1 failed - "object 'training' not found"
这是有趣的地方。它实际上并没有在编辑的行上失败。它实际上在下一行失败:forecast(fit, 1)$mean
换句话说,以下的事实上是有效的。
fits = foreach (i = 1:length(test)) %dopar% {
if (i > 1) {
training = c(train,test[1:i-1])
}
fracdiff(training, p, q, h=0.00001)
}
但是......
pred = foreach (i = 1:length(test), .combine=c) %dopar% {
forecast(fits[[i]], 1)$mean
}
抛出前面提到的关于"object 'training' not found"
编辑:根据要求......可重复的例子......
require(quantmod)
require(forecast)
require(fracdiff)
require(doParallel)
require(foreach)
cl <- makeCluster((detectCores() - 1), type="FORK")
registerDoParallel(cl)
predictionsThatWork <- function(train, test, cl){
training = train
pred = foreach (i = 1:length(test), .combine=c) %dopar% {
if (i > 1) {
training = c(train,test[1:i-1])
}
fit = nnetar(training, 8, P=1, 5)
forecast(fit, 1)$mean
}
return(pred)
}
predictionsThatDoNotWork <- function(train, test, cl){
training = train
pred = foreach (i = 1:length(test), .combine=c) %dopar% {
if (i > 1) {
training = c(train,test[1:i-1])
}
fit = fracdiff(training, 3, 1, h=0.00001)
forecast(fit, 1)$mean
}
return(pred)
}
ticker = 'IBM' #feel free to replace with ticker of your choice
getSymbols(ticker, from='2010-01-01', to='2016-08-31')
fullts = get(ticker)
returnTS = diff(log(fullts[,4]),lag=1)[-1]
returnTS = returnTS - mean(returnTS)
numObs = length(returnTS)
cutOff = ceiling(numObs*.85)
train = returnTS[1:cutOff-1]
test = returnTS[cutOff:numObs]
predictionsThatWork(train, test, cl)
predictionsThatDoNotWork(train, test, cl)
stopCluster(cl)
编辑2:好的,这个问题与并行性无关。这与fracdiff
和forecast
之间的互动有关。以下功能不起作用
anotherBrokenFunction <- function(train, test) {
training = train
print(exists('training'))
predictions = test
for (i in 1:length(test)){
print(exists('training'))
arf = fracdiff(x=training, nar=3, nma=1, h=0.00001)
print(exists('training'))
predictions[i] = forecast(arf, 1)$mean
print(exists('training'))
training = c(training, test[i])
}
return(predictions)
}
评估如下
> anotherBrokenFunction(train, test)
[1] TRUE
[1] TRUE
[1] TRUE
Error in eval(expr, envir, enclos) : object 'training' not found
答案 0 :(得分:1)
这是一个hacky修复,但有一个建议是在函数中添加arf$x <- training
:
anotherBrokenFunction <- function(train, test) {
training = train
predictions = test
for (i in 1:length(test)){
arf = fracdiff(x=training, nar=3, nma=1, h=0.00001)
arf$x <- training # add this
predictions[i] = forecast(arf, 1)$mean
training = c(training, test[i])
}
return(predictions)
}
out <- anotherBrokenFunction(train, test)
str(out)
# An ‘xts’ object on 2015-09-02/2016-08-31 containing:
# Data: num [1:252, 1] -0.000312 -0.000534 0.001913 0.000513 -0.000467 ...
# - attr(*, "dimnames")=List of 2
# ..$ : NULL
# ..$ : chr "IBM.Close"
# Indexed by objects of class: [Date] TZ: UTC
# xts Attributes:
# List of 2
# $ src : chr "yahoo"
# $ updated: POSIXct[1:1], format: "2016-09-15 09:56:46"
详细信息:forecast.fracdiff
调用getResponse
,fracdiff
getResponse
方法如下:
getAnywhere("getResponse.fracdiff")
# A single object matching ‘getResponse.fracdiff’ was found
# It was found in the following places
# registered S3 method for getResponse from namespace forecast
# namespace:forecast
# with value
# function (object, ...)
# {
# if (is.element("x", names(object)))
# x <- object$x
# else x <- eval.parent(parse(text = as.character(object$call)[2]))
# if (is.null(tsp(x)))
# x <- ts(x, frequency = 1, start = 1)
# return(x)
# }
# <bytecode: 0x7fd64bd8b698>
# <environment: namespace:forecast>
所以它首先查找fracdiff
对象中名为“x”的元素,否则它会查找as.character(object$call)[2]
(在这种情况下恰好是training
),生成错误。我们的想法是在training
对象中插入x
作为元素fracdiff
以抢占此错误。