在这种情况下,tapply(args是不等长)有什么问题?

时间:2016-09-14 20:23:51

标签: r tapply

数据取自http://open.canada.ca/data/en/dataset/b52664cf-bfd9-49ad-849a-cb88c92553b9(英文版)

 glacier <- read.csv("glacier.csv", stringsAsFactors = F)
 str(glacier)
'data.frame':   518 obs. of  6 variables:
 $ Ref_Date  : int  1977 1978 1979 1980 1981 1982 1983 1984 1985 1986 ...
 $ GEO       : chr  "Helm Glacier - southern Coast Mountains (Garibaldi Provincial Park), British Columbia" "Helm Glacier - southern Coast Mountains (Garibaldi Provincial Park), British Columbia" "Helm Glacier - southern Coast Mountains (Garibaldi Provincial Park), British Columbia" "Helm Glacier - southern Coast Mountains (Garibaldi Provincial Park), British Columbia" ...
 $ MEASURE   : chr  "Annual mass balance" "Annual mass balance" "Annual mass balance" "Annual mass balance" ...
 $ Vector    : chr  "v54326054" "v54326054" "v54326054" "v54326054" ...
 $ Coordinate: num  1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 1.1 ...
 $ Value     : chr  "-1460.0" "-780.0" "-2730.0" "-940.0" ...

tapply(X = as.numeric(glacier[glacier$MEASURE == "Annual mass balance", c("Value")]), 
                      INDEX = unique(glacier[ , 2]), FUN = median, na.rm = T)

给出错误: tapply错误(as.numeric(冰川[冰川$ MEASURE ==“年度质量平衡”,:   更改自定义更多 我检查了参数,它们对于tapply函数似乎很正常。不知道,有什么不对。提前谢谢。

编辑:

tapply(X = as.numeric(glacier[glacier$MEASURE == "Annual mass balance", c("Value")]), 
                      INDEX = glacier[ , 2], FUN = median, na.rm = T)

给出相同的错误

1 个答案:

答案 0 :(得分:0)

您正在尝试对冰川数据框进行子集化,我希望glacier$Measure !="Annual mass balance"中有一个或多个元素。因此glacier[glacier$MEASURE == "Annual mass balance", c("Value")]的列长度不等于:glacier[ , 2]的长度。如果这是真的那么你也需要对索引进行子集化。

以下是创建数据子集以提高可读性的解决方案:

glacier <- read.csv("01530102-eng.csv", stringsAsFactors = F)

glacierreduced<-glacier[glacier$MEASURE == "Annual mass balance",]
tapply(X = as.numeric(glacierreduced$Value),  INDEX = glacierreduced[ , 2],  
       FUN = median, na.rm = T)