Question

我有一个看起来像XML文件的文本文件，但它不是一个有效的XML文件。我该如何解析它？我正在使用Java。我需要最后一个标签的内容。

示例文件：

<h4 class="is24qa-objektbeschreibung-label padding-top-xl margin-bottom-              s">Objektbeschreibung</h4> 
<div class="is24-text margin-bottom"> 
<pre class="is24qa-objektbeschreibung">TEST TEST TEST </pre>

Answer 1

你可以这样使用jsoup。

package com.company;

import java.io.*;

import org.jsoup.Jsoup;
import org.jsoup.nodes.Document;
import org.jsoup.nodes.Element;
import org.jsoup.select.Elements;

public class Main {
    public static void main(String[] args) {
        String line;
        String cline = "";
        Document doc;
        try {
            BufferedReader br = new BufferedReader(new FileReader("input.txt"));

            while ((line = br.readLine()) != null) {
                cline = line;
            }

            doc = Jsoup.parse(cline);
            Elements elements = doc.select("body").first().children();
            for (Element el : elements)
                System.out.println("content: " + el.text());

        } catch (IOException e) {
            e.printStackTrace();
        }

    }

}

input.txt

<h4 class="is24qa-objektbeschreibung-label padding-top-xl margin-bottom-              s">Objektbeschreibung</h4>
<div class="is24-text margin-bottom">
<pre class="is24qa-objektbeschreibung">TEST TEST TEST </pre>

输出

/usr/lib/jvm/java-1.8.0-openjdk-amd64/bin/java -
content: TEST TEST TEST

Process finished with exit code 0

TEXT文件解析Java

1 个答案: