我有一个查询,我用“marketing_fee”提取“顾问”的所有记录。结果如下:
有没有办法按顾问(中间栏)对它们进行分组,但是加起来所有的marketing_fee?
我目前使用的代码只是收取最新费用。
select a.marketing_fee, v.Consultant, user.colorcode
from valuations v
join status_history sh on sh.ref = v.Ref
join user on user.username = v.Consultant
join answer a on a.title = v.Ref
where sh.status = 'booked' and sh.date between '2016-09-07 23:59:00' and '2016-09-14 23:59:00'
答案 0 :(得分:0)
这是你想要的吗?
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答案 1 :(得分:0)
尝试使用以下查询。
select SUM(IFNULL(a.marketing_fee,0))Marketing_Fee,
v.Consultant,
User.Colorcode
from valuations v
join status_history sh
on sh.ref = v.Ref
join user on user.username = v.Consultant
join answer a on a.title = v.Ref
where sh.status = 'booked' and
sh.date between '2016-09-07 23:59:00' and '2016-09-14 23:59:00'
group by v.Consultant,User.colorcode
答案 2 :(得分:-1)
我相信您可以按多列分组并在marketing_fee列上使用聚合函数。
select v.Consultant, SUM(a.marketing_fee), user.colorcode
from valuations v
join status_history sh on sh.ref = v.Ref join
user on user.username = v.Consultant
join answer a on a.title = v.Ref
where sh.status = 'booked' and sh.date between '2016-09-07 23:59:00' and '2016-09-14 23:59:00'
group by v.consultant, a.marketing_fee, user.colorcode