Question

我有一个动态名称的数组。我的数组可能超过3，取决于数组变量应该是唯一的

 $loopThrice = 3;
 $getSum = 0;
 $total = array();

 $array0 = array(5, 10, 15, 20, 25, 30);
 $array1 = array(1, 2, 3, 4, 5, 6);
 $array2 = array(2, 6, 8, 10, 12, 14);

 for($a=0; $a < $loopThrice; $a++){ // loop 3x to get unique array name

     foreach (${'array'.$a} as $key => $value) { // $array0, $array1, $array2,  
        //Right here is my problem, I'm not sure if this the correct way to get the sum of $array0,1,2

        //get the sum of array0,1,2 -- newarray(8, 18, 26, 34, 42, 50)
        $getSum += 

        //store newarray
        array_push($total, $getSum);


    }
 }

我需要得到像这样的输出

  print_r(total);

  Array ( 
       [0] => 8
       [1] => 18 
       [2] => 26 
       [3] => 34 
       [4] => 43 
       [5] => 50 
      )

Answer 1

为什么你没有使用多维数组？

$array = array(); // hungarian notation
$array[] = array(5, 10, 15, 20, 25, 30);
$array[] = array(1, 2, 3, 4, 5, 6);
$array[] = array(2, 6, 8, 10, 12, 14);

在这种情况下，您将拥有一个数组数组：

Array
(
[0] => Array
    (
        [0] => 5
        [1] => 10
        [2] => 15
        [3] => 20
        [4] => 25
        [5] => 30
    )

[1] => Array
    (
        [0] => 1
        [1] => 2
        [2] => 3
        [3] => 4
        [4] => 5
        [5] => 6
    )

[2] => Array
    (
        [0] => 2
        [1] => 6
        [2] => 8
        [3] => 10
        [4] => 12
        [5] => 14
    )
)

您可以使用嵌套的for循环：

$sumArray = array();
$arrayCount = count($array);
$elementCount = 0;

foreach($array as $subarray)
{
    $count = count($subarray);
    $elementCount = $elementCount < $count ? $count : $elementCount;
}

for($i = 0; $i < $elementCount; $i++)
{
    $sumArray[$i] = 0;

    for($j = 0; $j < $arrayCount; $j++)
    {
        $sumArray[$i] += $array[$j][$i];
    }
}

print_r($sumArray);

输出

Array
(
    [0] => 8
    [1] => 18
    [2] => 26
    [3] => 34
    [4] => 42
    [5] => 50
)

现在，如果你有一个不成比例的子数组（即每个子数组中不同的元素数），你仍然会得到某种结果，因为缺少的元素将被假定为0。所以，输入：

$array = array(); // hungarian notation
$array[] = array(5, 10, 15, 20, 25);
$array[] = array(1, 2, 3, 4, 5, 6);
$array[] = array(2, 6, 8, 10);

您仍会得到结果：

Array
(
    [0] => 8
    [1] => 18
    [2] => 26
    [3] => 34
    [4] => 30
    [5] => 6
)

Answer 2

多阵列是可行的方法，但你仍然可以这样做：

 $loopThrice = 3;
 $getSum = 0;
 $total = array();

 $array0 = array(5, 10, 15, 20, 25, 30);
 $array1 = array(1, 2, 3, 4, 5, 6);
 $array2 = array(2, 6, 8, 10, 12, 14);
 // find which arrray has the most values
 for($a=0; $a < $loopThrice; $a++){
     $max_index = (count(${'array'.$a}) > $max_index ? count(${'array'.$a}) : $max_index);
 }

 for($i=0; $i < $max_index; $i++){
      for($a=0; $a < $loopThrice; $a++){
           $total[$i] += ${'array'.$a}[$i];
     }
 }

 print_r($total);
 // prints Array ( [0] => 8 [1] => 18 [2] => 26 [3] => 34 [4] => 42 [5] => 50 )

Answer 3

这应该适合你：

$array0 = array(5, 10, 15, 20, 25, 30);
$array1 = array(1, 2, 3, 4, 5, 6);
$array2 = array(2, 6, 8, 10, 12, 14);

$var_prefix = 'array';
$arr_count = 0;
$max_fields = 0;

while(isset(${$var_prefix.$arr_count})) {
    $data[] = ${$var_prefix.$arr_count};
    if(count(${$var_prefix.$arr_count})>$max_fields) {
        $max_fields = count(${$var_prefix.$arr_count});
    };

    $arr_count++;
}

for($i=0; $i<$max_fields; $i++) {
    $result[$i] = array_sum(array_column($data, $i));
}

echo '<pre>';
print_r($result);
echo '</pre>';
die();

PHP：如何使用动态数组名称获取多个数组的总和

3 个答案: