Question

我有一份oozie工作如下：

<action name="action1">
    <ssh xmlns="uri:oozie:ssh-action:0.1">
        <host>${sshHost}</host>
        <command>${scriptDir}/${scriptName}</command>
        <capture-output/>
    </ssh>
    <ok to="scheduleOkAction" />
    <error to="scheduleErrorAction" />
</action>
<action name="action2">
    <email xmlns="uri:oozie:email-action:0.1">
        <to>${emailToAddress}</to>
        <subject>Workflow failed to run</subject>
        <body>
          [Workflow - ${wf:name()}] failed to run.
          Stack Trace
          ${wf:actionData('action1')['ERROR']}
        </body>
    </email>
    <ok to="kill" />
    <error to="kill" />
</action>
<action name="action3">
    <email xmlns="uri:oozie:email-action:0.1">
        <to>${emailToAddress}</to>
        <subject>Success</subject>
        <body>
          [Workflow - ${wf:name()}] - OK.
          ${wf:actionData('action1')['SUCCESS_CODE']}
        </body>
    </email>
    <ok to="kill" />
    <error to="kill" />
</action>

当＆＃39; action1＆＃39;没有异常，工作流程将我带到＆＃39; action3＆＃39;并向我发送了一封电子邮件＆＃39; SUCCESS_CODE＆＃39; actionData。但是当＆＃39; action1＆＃39;抛出一个例外，工作流程将我带到＆＃39; action2＆＃39;并向我发送了一封电子邮件没有＆＃39; ERROR＆＃39; actionData。

在Oozie发生错误时，松散所有actionData是否有效？或者我错过了什么？

Oozie actionData在错误时不可用

0 个答案: