请参阅下面的样本表。我的表有ID,ID_Type,Lag和Row_Num。我需要在下面创建“New_Col”列。我接近使用MAX窗口功能,但我还没有成功。任何帮助都将非常感激 - 如果窗口功能不是要走的路,我绝对愿意接受建议。
以下是我用来到下面的示例表的SQL:
SELECT ID,
ID_TYPE,
LAG(ID_TYPE) OVER (ORDER BY Row_Num) AS Lag,
Row_Num
FROM (SELECT ID,
CASE WHEN ID LIKE '%Exc%'
THEN ID
END AS ID_Type,
Row_Num
FROM Source_Table)
样本表:
ID ID_Type Lag Row_Num
Exc Exc 1
10R46 Exc 2
10R46 3
100R91 4
Non_Exc Non_Exc 5
10R91 Non_Exc 6
10M95 7
期望的输出:
ID ID_Type Lag New_Col Row_Num
Exc Exc 1
10R46 Exc Exc 2
10R46 Exc Exc 3
100R91 Exc 4
Non_Exc Non_Exc Non_Exc 5
10R91 Non_Exc Non_Exc 6
10M95 Non_Exc 7
答案 0 :(得分:0)
一种方法是生成范围键
Declare @YourTable table (ID varchar(50),ID_Type varchar(50),Lag varchar(50),Row_Num int)
Insert into @YourTable values
('Exc','Exc','',1),
('10R46','','Exc',2),
('10R46','','',3),
('100R91','','',4),
('Non_Exc','Non_Exc','',5),
('10R91','','Non_Exc',6),
('10M95','','',7)
;with cteR1 as (Select ID_Type,R1=min(Row_Num) from @YourTable Where ID_Type<>'' Group by ID_Type
), cteR2 as (Select A.ID_Type,A.R1,R2=isnull(min(B.R1),9999)-1 From cteR1 A Left Join cteR1 B on (B.R1>A.R1) Group By A.ID_Type,A.R1)
Select A.ID
,A.ID_Type
,A.Lag
,New_Col=B.ID_Type
,A.Row_Num
From @YourTable A
Join cteR2 B on Row_Num between R1 and R2
Order By Row_Num
返回
ID ID_Type Lag Row_Num New_Col
Exc Exc 1 Exc
10R46 Exc 2 Exc
10R46 3 Exc
100R91 4 Exc
Non_Exc Non_Exc 5 Non_Exc
10R91 Non_Exc 6 Non_Exc
10M95 7 Non_Exc
答案 1 :(得分:0)
将IGNORE NULLS规范添加到LAG窗口功能可以实现我的目标。
"c = a + b"
返回:
SELECT ID,
ID_TYPE,
LAG(ID_TYPE IGNORE NULLS) OVER (ORDER BY Row_Num) AS Lag,
Row_Num
FROM (SELECT ID,
CASE WHEN ID LIKE '%Exc%'
THEN ID
END AS ID_Type,
Row_Num
FROM Source_Table)