Question

这个错误在substring方法上被抛出，我发现很多线程处理这个问题，但我遇到的问题似乎有所不同。我知道如果你的字符串比你的子串（开始，结束）大小短，它会抛出这个错误，但是在将任何东西传递给方法调用之前抛出这个错误。

我正在运行一个休眠标准：

    public static List<Object[]> baseQuery() throws HibernateException{
    Session session = getSession();
    Criteria criteria = session.createCriteria(CsvDataEntity.class);
    ProjectionList projectionList = Projections.projectionList();
    projectionList.add(Projections.property("clearanceMainCat"));
    projectionList.add(Projections.property("clearanceDt"));
    projectionList.add(Projections.property("vertRadians"));
    projectionList.add(Projections.property("latitude"));
    criteria.setProjection(projectionList);

    List<Object[]> list = criteria.list();
    return list;
    }

然后我在这里使用查询：

    List<Object[]> fullList = baseQuery();
    String address = "400 Pine St, Seattle, WA 98101";
    String distance = "1";
    String years = "8";

    //create 'context' for GoogleMaps GeoCode API, geocode user-defined address
    GeoApiContext context = new GeoApiContext().setApiKey("Foobar");
    GeocodingResult[] result = geocode(context, address).await();
    Geometry coordinates = result[0].geometry;

    //store user request lat & lng from address supplied from form
    double longitude = coordinates.location.lng;
    double latitude = coordinates.location.lat;

    //user requested distance
    double requestedDistanceInMiles = Double.parseDouble(distance);

    //list to store all the crimes within the specified distance
    List<CrimeModel> crimeList = new ArrayList<>();

    for (Object[] record : fullList) {

        //verifying crime was commmitted within user-defined distance
        Boolean withinDistance = false;
        double rowLng = Double.parseDouble((String)record[2]);
        double rowLat = Double.parseDouble((String)record[3]);
        double milesBetween =     (haversineDistance(latitude,rowLat,longitude,rowLng,0,0)) / 1609.34;

        if (milesBetween <= requestedDistanceInMiles) {
            withinDistance = true;
        }

        //verifying crime was committed within user-defined time-range
        Boolean withinTimeRange =false;
        double requestedYears = Double.parseDouble(years);
        long requestedDays = Math.round(requestedYears * 365);
        String objectDate = (String) record[1];
        String recordDateAsString = objectDate.substring(0, 10);

查询有效，它返回的日期+时间字符串肯定超过十个字符。奇怪的是，我在第4行放置一个断点，调试，查询运行正常，但然后它在我发布的调用substring（）的片段的底部抛出错误。换句话说，我的String应该具有必要的长度，但在此错误之前它甚至没有被传入。有没有人知道为什么在它还没有被执行时会被抛出？我在Spring MVC中运行它，这是我能想到的唯一可能导致一些奇怪情况发生的事情。感谢。

Answer 1

就像@David Wallace提到的那样，因为数据库太大了，偶尔会丢失记录，并且在从查询中填充List之后，会抛出错误。我对这些进行了简单的处理以跳过它们（由于缺少记录，查询中的所有四列都需要处理），一切正常。

SELECT L.LocationDesc
    ,FI.LocationName
    ,FI.CreatedDate
    ,FI.FileName
FROM dbo.FileImport FI
LEFT OUTER JOIN dbo.Location L ON FI.LocationName = L.LocationDesc
    AND CAST(FI.CreatedDate AS DATE) = '2016-09-14'
WHERE L.LocationDesc IS NULL

模糊＆＃39; StringIndexOutOfBoundsException＆＃34;

1 个答案: