是否可以将不同的标签链接到同一视图? 现在我有:
<ion-tabs class="tabs-icon-top tabs-color-active-positive">
<ion-tab title="Dashboard" icon-off="ion-ios-speedometer-outline" icon-on="ion-ios-speedometer" active="active.dashboard" >
<ion-nav-view name="tab-app"></ion-nav-view>
</ion-tab>
<ion-tab title="Reports" icon-off="ion-ios-pie-outline" icon-on="ion-ios-pie">
<ion-nav-view name="tab-app"></ion-nav-view>
</ion-tab>
<ion-tab title="Create" icon-off="ion-ios-plus" icon-on="ion-plus-circled" >
<ion-nav-view name="tab-app"></ion-nav-view>
</ion-tab>
<ion-tab title="Approvals" icon-off="ion-ios-bell-outline" icon-on="ion-ios-bell">
<ion-nav-view name="tab-app"></ion-nav-view>
</ion-tab>
<ion-tab title="Settings" icon-off="ion-ios-gear-outline" icon-on="ion-ios-gear" href="#/tab/settings">
<ion-nav-view name="tab-settings"></ion-nav-view>
</ion-tab>
</ion-tabs>
但是,这些选项卡中的每一个都只是tab-app的不同实例,控制器会重新加载,并且它们不共享任何属性。
如何让标签共享相同的视图?我想将它们链接在一起,让控制器根据所选的任何选项卡进行操作。谢谢!
更新,添加路由:
.config(function($stateProvider, $urlRouterProvider) {
// Ionic uses AngularUI Router which uses the concept of states
// Learn more here: https://github.com/angular-ui/ui-router
// Set up the various states which the app can be in.
// Each state's controller can be found in controllers.js
$stateProvider
// setup an abstract state for the tabs directive
.state('tab', {
url: '/tab',
abstract: true,
templateUrl: 'templates/tabs.html',
controller: 'TabCtrl'
})
// Each tab has its own nav history stack:
.state('tab.app', {
url: '/app',
params: {state_location: null},
views: {
'tab-app': {
templateUrl: 'templates/tab-app.html',
controller: 'AppCtrl'
}
}
})
// if none of the above states are matched, use this as the fallback
$urlRouterProvider.otherwise('/tab/app');
})
答案 0 :(得分:-1)
这与控制器共享数据基本相同。