我有一个csv文件(in.csv)
col1, col2, col3
Kapitän, Böse, Füller
...
我想创建一个词典列表:
a = [{'col1': 'Kapitän', 'col2': 'Böse', 'col3': 'Füller'},{...}]
使用Python 3,它正在使用
import codecs
with codecs.open('in.csv', encoding='utf-8') as f:
a = [{k: v for k, v in row.items()}
for row in csv.DictReader(f, skipinitialspace=True)]
print(a)
(我已经从convert csv file to list of dictionaries获得了此代码。)
不幸的是,我需要这个用于Python 2,但我不喜欢它。
我试图了解https://docs.python.org/2.7/howto/unicode.html,但我觉得我太傻了,因为
import codecs
f = codecs.open('in.csv', encoding='utf-8')
for line in f:
print repr(line)
给了我
u'col1,col2,col3\n'
u'K\xe4pten,B\xf6se,F\xfcller\n'
u'\n'
你有Python 2的解决方案吗?
这里解决了类似的问题:Creating a dictionary from a csv file?但是通过标记的解决方案,我得到('K\xc3\xa4pten', 'B\xc3\xb6se', 'F\xc3\xbcller')
。可能很容易编辑它以获取[{u'col1': u'K\xe4pten', u'col2': u'B\xf6se', u'col3': u'F\xfcller'}]
?
答案 0 :(得分:1)
你可以利用csv lib来完成这项工作。
import csv
li_of_dicts = []
with open('in.csv', 'r') as infile:
reader = csv.DictReader(infile, encoding='utf-8')
for row in reader:
li_of_dicts.append(row)
答案 1 :(得分:0)
打印使用print line
代替print repr(line)
对于dict我使用此解决方案
https://docs.python.org/2/library/csv.html#csv-examples
csv模块不直接支持读取和写入Unicode
import codecs
import csv
def utf_8_encoder(unicode_csv_data):
for line in unicode_csv_data:
yield line.encode('utf-8')
def unicode_csv_reader(unicode_csv_data, dialect=csv.excel, **kwargs):
# csv.py doesn't do Unicode; encode temporarily as UTF-8:
csv_reader = csv.reader(utf_8_encoder(unicode_csv_data),
dialect=dialect, **kwargs)
for row in csv_reader:
# decode UTF-8 back to Unicode, cell by cell:
yield [unicode(cell, 'utf-8') for cell in row]
with codecs.open('in.csv', encoding='utf-8') as f:
reader = unicode_csv_reader(f)
keys = [k.strip() for k in reader.next()]
result = []
for row in reader:
d=dict(zip(keys, row))
result.append(d)
for d in result:
for k, v in d.iteritems():
print k, v
print result