我正在使用MIPS MARS程序集编写程序，该程序执行不同的数学计算，并且我无法理解为什么.data部分中的字符串值在程序开头打印为块而不是单独的线条。我也在将值打印到正确的语句旁边时遇到问题。
.data
NL: .asciiz "\n" #NL=new line varible kinda name
addition: .ascii "The value of a + b = \n"
subtraction: .ascii "The value of a - b = \n "
prob_3: .ascii "The value of (a + b) - 8 = \n"
prob_4: .ascii "The value of (a + b) - (c + d) = \n"
prob_5: .ascii "The value of ((a + b) + (d - c) + 17 = \n"
.text
li $s0, 8
li $s1, 8
li $s2, 16
li $s3, 8
la $a0, addition
li $v0, 4
syscall
add $t1, $s0, $s1
li $v0, 1
add $a0, $t1, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, subtraction
li $v0, 4
syscall
sub $t2, $s0, $s1
li $v0, 1
sub $a0, $t2, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_3
li $v0, 4
syscall
subi $t3, $t1, 8
li $v0, 1
sub $a0, $t3, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_4
li $v0, 4
syscall
add $t4, $s2, $s3
sub $t5, $t1, $t4
li $v0, 1
sub $a0, $t5, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_5
li $v0, 4
syscall
sub $t6, $s3, $s2
add $t7, $t1, $t6
addi $t8, $t7, 17
li $v0, 1
add $a0, $t8, $zero
syscall
我得到的结果：
The value of a + b =
The value of a - b =
The value of (a + b) - 8 =
The value of (a + b) - (c + d) =
The value of ((a + b) + (d - c) + 17 =
16
The value of a - b =
The value of (a + b) - 8 =
The value of (a + b) - (c + d) =
The value of ((a + b) + (d - c) + 17 =
0
The value of (a + b) - 8 =
The value of (a + b) - (c + d) =
The value of ((a + b) + (d - c) + 17 =
8
The value of (a + b) - (c + d) =
The value of ((a + b) + (d - c) + 17 =
-8
The value of ((a + b) + (d - c) + 17 =
25
结果我试图获得：
The value of a + b = 16
The value of a - b = 0
The value of (a + b) - 8 = 8
The value of (a + b) - (c + d) = -8
The value of ((a + b) + (d - c) + 17 = 25
有人可以帮我解决这个问题吗？
答案 0 :(得分：3)
您的\n细分中定义的字符串末尾不应包含换行符.data。换行符将未来的输出推送到下一行，因此您在字符串后面打印的数字将被放置在其后的行上。
您还应该对这些字符串使用以null结尾的字符串（.asciiz）。这就是为什么你要立刻打印所有的声明;代码不知道何时停止打印，因为没有终止字符。
答案 1 :(得分：0)
更新了更正后的代码：
.data
NL: .asciiz "\n" #NL=new line varible kinda name
prob_1: .asciiz "The value of a + b = "
prob_2: .asciiz "The value of a - b = "
prob_3: .asciiz "The value of (a + b) - 8 = "
prob_4: .asciiz "The value of (a + b) - (c + d) = "
prob_5: .asciiz "The value of ((a + b) + (d - c) + 17 = "
.text
li $s0, 8
li $s1, 8
li $s2, 16
li $s3, 8
la $a0, prob_1
li $v0, 4
syscall
add $t1, $s0, $s1
li $v0, 1
add $a0, $t1, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_2
li $v0, 4
syscall
sub $t2, $s0, $s1
li $v0, 1
sub $a0, $t2, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_3
li $v0, 4
syscall
subi $t3, $t1, 8
li $v0, 1
sub $a0, $t3, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_4
li $v0, 4
syscall
add $t4, $s2, $s3
sub $t5, $t1, $t4
li $v0, 1
sub $a0, $t5, $zero
syscall
la $a0, NL
li $v0, 4
syscall
la $a0, prob_5
li $v0, 4
syscall
sub $t6, $s3, $s2
add $t7, $t1, $t6
addi $t8, $t7, 17
li $v0, 1
add $a0, $t8, $zero
syscall