Question

我正在制作一个涉及抽认卡的学习应用程序。它分为几个科目。每个科目（生物学，物理学）都有一套甲板（unitone，unittwo）。每个牌组都有一组牌（术语和定义）。我希望我的网址看起来像 localhost：8000 / biology / unitone /但是我在将两个URL参数放在一个URL中时遇到了麻烦。

models.py

class Subject(models.Model):
    subject_name = models.CharField(max_length=100)
    description = models.TextField()

    def __str__(self):
        return self.subject_name

    def get_absolute_url(self):
        return reverse('card:index')

class Deck(models.Model):
    deck_name = models.CharField(max_length=100)
    subject = models.ForeignKey(Subject, on_delete=models.CASCADE)

    def __str__(self):
        return self.deck_name

class Card(models.Model):
    term = models.CharField(max_length=100)
    definition = models.TextField()
    deck = models.ForeignKey(Deck, on_delete=models.CASCADE)

    def __str__(self):
        return self.term

views.py

class IndexView(generic.ListView):
   template_name = 'card/index.html'
   context_object_name = 'subjects'

   def get_queryset(self):
       return Subject.objects.all()

class SubjectView(DetailView):
    model = Subject
    slug_field = "subject"
    template_name = 'card/subject.html'

class DeckView(DetailView):
    model = Deck
    slug_field = "deck"
    template_name = 'card/deck.html'

urls.py

# localhost:8000/subjects/1 (biology)
url(r'^subjects/(?P<pk>[0-9]+)/$', views.SubjectView.as_view(), name='subject')


# localhost:8000/subjects/1/1 (biology/unitone)
url(r'^subjects/(?P<pk>[0-9]+)/(?P<pk>[0-9]+)/$', views.DeckView.as_view(), name='deck'),

urls.py中的第二个网址是我遇到的问题。它不是有效的网址。

Answer 1

您不能拥有多个具有相同名称的参数。您必须为每个参数指定一个唯一的名称，例如：

url(r'^subjects/(?P<pk>[0-9]+)/(?P<deck>[0-9]+)/$', views.DeckView.as_view(), name='deck'),

在DeckView中，您可以self.kwargs['pk']和self.kwargs['deck']访问它们。

Answer 2

有一种方法可以重写DetailViews

urls.py

url(r'^subjects/(?P<subjects>\w+)/(?P<deck>\w+)/$', views.DeckView.as_view(), name='deck'),

views.py

class DeckView(DetailView):
    model = Deck
    # slug_field = "deck" # you don't need it 
    template_name = 'card/deck.html'


    def get_object(self, subjects, deck):
        subject_obj = Subject.objects.filter(subject_name=subjects).first()
        obj = Deck.objects.filter(subject=subject_obj,deck_name=deck).first()
        return obj


    def get(self, request, subjects, deck):
        self.object = self.get_object(subjects, deck)
        context = self.get_context_data(object=self.object)
        return self.render_to_response(context)

然后访问localhost:8000/subjects/biology/unitone/

Django：多个URL参数

2 个答案: