在C#中动态计算每个字符的最佳方法是什么?
给定的
string sample = "Foe Doe";
它应输出类似
的内容f = 1
o = 2
e = 2
d = 1
计算单个角色很容易,但在我的考试中这有点棘手,我只能想象一个获得所有独特角色的解决方案 - >然后将它存储在一个集合(最好是一个数组)中,然后将它存储在数组和字符串的嵌套for循环中。
有比这更好的解决方案吗?
答案 0 :(得分:7)
使用LINQ
sample.GroupBy(c => c).Select(c => new { Char = c.Key, Count = c.Count()});
答案 1 :(得分:2)
您可以使用类似于字典的Lookup<k,e>
:
var charLookup = sample.Where(char.IsLetterOrDigit).ToLookup(c => c); // IsLetterOrDigit to exclude the space
foreach (var c in charLookup)
Console.WriteLine("Char:{0} Count:{1}", c.Key, charLookup[c.Key].Count());
答案 2 :(得分:1)
您可以使用Linq:
sample.GroupBy(x => x).Select(x => $"{x.Key} = {x.Count()}").
调整你可以删除空字符,不区分大小写等。
str.ToLower().GroupBy(x => x).Where(x => x.Key != ' ').Select(x => $"{x.Key} = {x.Count()}")
等等..
答案 3 :(得分:0)
class Program
{
static void Main(string[] args)
{
const string inputstring = "Hello World";
var count = 0;
var charGroups = (from s in inputstring
group s by s into g
select new
{
c = g.Key,
count = g.Count(),
}).OrderBy(c => c.count);
foreach (var x in charGroups)
{
Console.WriteLine(x.c + ": " + x.count);
count = x.count;
}
Console.Read();
}
}
答案 4 :(得分:0)
由于string
实现IEnumerable<char>
,您可以使用Linq .Where()和.GroupBy()扩展来计算字母并消除空格。
string sample = "Foe Doe";
var letterCounter = sample.Where(char.IsLetterOrDigit)
.GroupBy(char.ToLower)
.Select(counter => new { Letter = counter.Key, Counter = counter.Count() });
foreach (var counter in letterCounter)
{
Console.WriteLine(String.Format("{0} = {1}", counter.Letter, counter.Counter));
}
答案 5 :(得分:0)
string str = "Orasscleee";
Dictionary<char,int> c=new Dictionary<char, int>();
foreach (var cc in str)
{
char c1 = char.ToUpper(cc);
try
{
c.Add(c1,1);
}
catch (Exception e)
{
c[c1] = c[c1] + 1;
}
}
foreach (var c1 in c)
{
Console.WriteLine($"{c1.Key}:{c1.Value}");
}
答案 6 :(得分:-1)
string str;
int i, cnt;
Console.WriteLine("Enter a sentence");
str = Console.ReadLine();
char ch;
for (ch = (char)65; ch <= 90; ch++)
{
cnt = 0;
for ( i = 0; i < str.Length; i++)
{
if (ch == str[i] || (ch + 32) == str[i])
{
cnt++;
}
}
if (cnt > 0)
{
Console.WriteLine(ch + "=" + cnt);
}
}
Console.ReadLine();
答案 7 :(得分:-1)
string new_string= String.Concat(s.OrderBy(c => c)); //for sorting string
for (int i = 0; i < new_string.Length; i++)
{
int count = 0;
for (int j = i; j < new_string.Length; j++)
{
if (new_string[i] == new_string[j])
{
count++;
}
else
{
if (count == 0)
{ count = 1; }
break;
}
}
Console.WriteLine("count for "+new_string[i]+"is: "+count);
new_string=new_string.Remove(0, count);
i = 0;
}
Console.ReadKey();
}