Question

我试图创建一个程序来接受你的生日（yymmdd），用字符串替换数字并输出你的真实birthname＆＃34;。

问题是循环只输出键入提示的最后一个数字的字符串，+ =输出自身。我有点希望它会遍历循环并在birthname变量中添加一个接一个的字符串。

（这是我的第一个自己的代码，所以要温柔）：）

<object>

Answer 1

您可以在循环中使用它 birthName + =“你想要的”

Answer 2

var birthDate = prompt("write your birthdate!");
var birthDateSplitter = birthDate.split("");
var len = birthDateSplitter.length;
var birthName = '';
var i = 0;

for (i; i < len; i++) {

if (birthDateSplitter[i] == 9) {
    birthName += "do";
} else if (birthDateSplitter[i] == 8) {
    birthName += "ka";
} else if (birthDateSplitter[i] == 7) {
    birthName += "mu";
} else if (birthDateSplitter[i] == 6) {
    birthName += "ssa";
} else if (birthDateSplitter[i] == 5) {
    birthName += "tto";
} else if (birthDateSplitter[i] == 4) {
    birthName += "ti";
} else if (birthDateSplitter[i] == 3) {
    birthName += "le";
} else if (birthDateSplitter[i] == 2) {
    birthName += "pa";
} else if (birthDateSplitter[i] == 1) {
    birthName += "bu";
} else {
    birthName += "vi";
} 

}

alert("Your real birthname is " + birthName);

也许＆＃34; switch-case＆＃34;这将是一个更好的解决方案

Answer 3

if (birthDateSplitter[i] == 9) {
    birthName += "do";
} else if (birthDateSplitter[i] == 8) {
    birthName += "ka";
//...

但更好的是，你可以摆脱if s：

var birthDate = prompt("write your birthdate!");
var birthDateSplitter = birthDate.split("");
var len = birthDateSplitter.length;
var birthName = '';
var i = 0;
var birthNameParts = ['vi', 'bu', 'pa', 'le', 'ti', 'tto', 'ssa', 'mu', 'ka', 'do'];

for (i; i < len; i++) {
    birthName += birthNameParts[birthDateSplitter[i]];
}

Answer 4

以下是我将如何处理：

var birthDateSplitted = prompt('write your birthdate!').split(''),
    nameParts = ['vi', 'bu', 'pa', 'le', 'ti', 'tto', 'ssa', 'mu', 'ka', 'do'],
    birthName = birthDateSplitted.map(function(n) { return nameParts[n]; }).join('');

alert('Your real birthname is ' + birthName);

https://jsbin.com/gisubop/edit?js,output

Javascript - 将数字转换为字符串

4 个答案: