Question

我有以下查询

select Case.casekey, LoginName, startdatedate, SenttoClientDate
from case with (nolock)
where SenttoClientDate = dateadd(day,-1, cast(getdate() as date))

这将返回{senttoclientdate} =昨天的结果。

问题是，如果我在星期一运行这个，我会得到星期天的结果，但我想要上一个工作日。因此，如果我在星期一跑，我想要星期五的结果。

Answer 1

你可以这样做：

WHERE SenttoClientDate = (SELECT  DATEADD(DAY, CASE DATENAME(WEEKDAY, GETDATE()) 
                    WHEN 'Sunday' THEN -2 
                    WHEN 'Monday' THEN -3 
                    ELSE -1 END, DATEDIFF(DAY, 0, GETDATE())))

Answer 2

在日期部分中加入案例

where SentToClientDate = 
    case when datepart(dw,getdate()) = 2 then dateadd(day,-3,getdate()) -- Monday is day 2, for no reason whatsoever
         else dateadd(day,-1,getdate())
    end

Answer 3

在何处条件下使用套管如下，

    select Case.casekey, LoginName, startdatedate, SenttoClientDate
    from case with (nolock)
    where SentToClientDate = 
    case when datepart(dw,getdate()) = 2 then dateadd(day,-3,getdate())
         when datepart(dw,getdate()) = 1 then dateadd(day,-2,getdate())
         else dateadd(day,-1,getdate())
    end

Answer 4

请你试试这个，这是非常简单和完美的解决方案：

SELECT  Case.casekey, LoginName, startdatedate, SenttoClientDate
FROM case with (nolock)
WHERE SenttoClientDate = 
CAST(DATEADD(dd, 
    CASE WHEN DATEPART(weekday, GETDATE()) = 6 THEN  0 
    ELSE (6-(DATEPART(weekday, GETDATE())+7)) END, GETDATE()) AS DATE)

SQL上一个工作日

4 个答案: