Question

我正在尝试用Java创建HTTP PATCH请求，但尽管我付出了努力，但这并不起作用。我正在尝试修补一个Json，这是我的代码：

    HttpResponse response = null;
    BufferedReader rd = null;
    StringBuffer result = new StringBuffer();
    String line = "";

    HttpClient httpclient = HttpClients.createDefault();
    HttpPatch httpPatch = new HttpPatch("http://myURL");

    JsonArrayBuilder Abuilder = Json.createArrayBuilder();
    JsonObjectBuilder oBuilder = Json.createObjectBuilder();
    for(int i=0;i<48;i++){
        Abuilder.add(i+1);
    }
    oBuilder.add("date", "2016-09-08");
    oBuilder.add("values",Abuilder);

    JsonObject jo = Json.createObjectBuilder().add("puissance", Json.createObjectBuilder().add("curves",Json.createArrayBuilder().add(oBuilder))).build();

    try{            
        //Execute and get the response.

        StringEntity params =new StringEntity(jo.toString());

        params.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
        httpPatch.setEntity(params);

        response = httpclient.execute(httpPatch);

        System.out.println("Response Code : " + response.getStatusLine().getStatusCode());
        rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
        while ((line = rd.readLine()) != null) {
                        System.out.println(line);
                        result.append(line);
        }

    }catch(Exception e){

    }

当我执行此请求时，我得到了

＆＃34; 400错误：请求的标题名称无效＆＃34;。

当我使用Postman执行此请求时，这工作正常。

我对HTTP请求很陌生，所以不要犹豫，询问您是否需要更多详细信息。

Answer 1

StringEntity.setContentEncoding用于设置编码类型，

您应该使用StringEntity.setContentType来设置 ContentType

Answer 2

问题-

RestTemplate restTemplate = new RestTemplate();
restTemplate.patchForObject("http://localhost:8080/employee/1", requestBody, String.class);

解决方案-

RestTemplate restTemplate = new RestTemplate();
restTemplate.postForObject("http://localhost:8080/employee/1?_method=patch", requestBody, String.class);

Java中的HTTP PATCH请求

2 个答案: