Question

我在RegEx下方验证字符串..

var str = "Thebestthingsinlifearefree";
var patt = /[^0-9A-Za-z !\\#$%&()*+,\-.\/:;<=>?@\[\]^_`{|}~]*/g;
var res = patt.test(str);

结果将始终为true但我认为它会给出错误..因为我检查任何不在patt变量中的模式......

给定的字符串有效，它只包含带大写和小写字母的字母。不确定模式有什么问题。

Answer 1

这是您的代码：

＆＃13;

var str = "Thebestthingsinlifearefree";
var patt = /[^0-9A-Za-z !\\#$%&()*+,\-.\/:;<=>?@\[\]^_`{|}~]*/g;
console.log(patt.test(str));

＆＃13;

正则表达式

/[^0-9A-Za-z !\\#$%&()*+,\-.\/:;<=>?@\[\]^_`{|}~]*/g

将匹配任何内容，因为它接受长度为0的匹配，因为量词*。

只需添加锚点：

＆＃13;

var str = "Thebestthingsinlifearefree";
var patt = /^[^0-9A-Za-z !\\#$%&()*+,\-.\/:;<=>?@\[\]^_`{|}~]*$/;
console.log(patt.test(str));

＆＃13;

这是一个解释或你的正则表达式：

[^0-9A-Za-z !\\#$%&()*+,\-.\/:;<=>?@\[\]^_`{|}~]* match a single character not present in the list below

    Quantifier: * Between zero and unlimited times, as many times as possible, giving back as needed [greedy]
    0-9 a single character in the range between 0 and 9
    A-Z a single character in the range between A and Z (case sensitive)
    a-z a single character in the range between a and z (case sensitive)
     ! a single character in the list  ! literally
    \\ matches the character \ literally
    #$%&()*+, a single character in the list #$%&()*+, literally (case sensitive)
    \- matches the character - literally
    . the literal character .
    \/ matches the character / literally
    :;<=>?@ a single character in the list :;<=>?@ literally (case sensitive)
    \[ matches the character [ literally
    \] matches the character ] literally
    ^_`{|}~ a single character in the list ^_`{|}~ literally

Answer 2

请注意：

通过代码中的否定条件（!patt.test...）更好地表达对缺失模式的搜索。
您需要通过在前面添加反斜杠（.）来转义某些字符，例如(，)，?，\等。

＆＃13;

var str = "Thebestthingsinlifearefree";
var patt = /[0-9A-Za-z !\\#$%&\(\)*+,\-\.\/:;<=>\?@\[\]^_`\{|\}~]/;
var res = !patt.test(str);
console.log(res);

＆＃13;

这将按预期打印false。

RegEx模式测试在javascript中失败

2 个答案: