Question

我正在尝试从Java代码调用JavaScript函数。我的代码如下：

ScriptEngineManager manager = new ScriptEngineManager();
                ScriptEngine engine = manager.getEngineByName("JavaScript");

                String script = baseUrl + "UIConfigurator/includes/js/DataCaptureFramework.js";                 

                  try {
                    LOGGER.info("evaluating engine");
                    LOGGER.info(script);
                    URL url1 = new URL(script);
                    LOGGER.info("url1 "+url1.getPath()+url1);

                    BufferedReader in = new BufferedReader(
                    new InputStreamReader(url1.openStream()));
                    String inputLine = null;
                    StringBuffer buffer = new StringBuffer();
                    while ((inputLine = in.readLine()) != null)
                        buffer.append(inputLine);                   
                    LOGGER.info(buffer.toString());
                    engine.eval(buffer.toString());                     


                } catch (Exception e) {
                    // TODO Auto-generated catch block
                    LOGGER.error(e.toString());
                    LOGGER.error("Throwing error in the catch part"); 
                }
                Invocable inv = (Invocable) engine;
                try {
                    LOGGER.info("invoking function");
                    inv.invokeFunction("displayDataCapturePopUp("+user.getOrgId()+","+user.getId()+","+session.getLoginType()+");");
                } catch (NoSuchMethodException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                } catch (ScriptException e) {
                    // TODO Auto-generated catch block
                    LOGGER.error("throwing error in catch block of invoking engine and function");
                }

当我运行此代码时，它会给我以下错误：

11：53：50,847错误[登录] javax.script.ScriptException： sun.org.mozilla.javascript.internal.EcmaError：ReferenceError： “jQuery”没有定义。（＃1）in 第1 11：53：50,847错误[登录]捕获中的投掷错误第11：53：50,848条信息[登录]调用函数11：53：50,848错误 [STDERR] java.lang.NoSuchMethodException：没有这样的方法： displayDataCapturePopUp（301,1373864,0）;

我尝试过很多东西，但仍然无法摆脱这种情况。请告诉我我做错了什么。我试图从JavaScript调用以下函数。

function displayDataCapturePopUp(orgId,userId,loginTypeId){ jQuery("              <link/>", {rel: "stylesheet",type: "text/css",href: 
"/UIConfigurator/includes/css/librarycss/jquery-ui.min.css"}).appendTo("head"); jQuery("<link/>", {rel: "stylesheet",type: "text/css",href: 
"/UIConfigurator/includes/css/DataCaptureFramework.css"}).appendTo("head"); jQuery("<link/>", {rel: "stylesheet",type: "text/css",href: 
"/UIConfigurator/includes/css/librarycss/tooltipster.css"}).appendTo("head");   jQuery("<link/>", {rel: "stylesheet",type: "text/css",href: 
"/UIConfigurator/includes/css/librarycss/jquery.alerts.css"}).appendTo("head"); 
jQuery.getScript('/UIConfigurator/includes/js/UiAjaxInteraction.js',function()  {       
jQuery.getScript('/iONjsLib/js/jquery-ui-1.10.4.min.js',function()      {           
jQuery.getScript('/iONjsLib/js/jquery.tooltipster.min.js',function()            {               
jQuery.getScript('/UIConfigurator/includes/js/libraryjs/jquery.alerts.js',function()                {                   
jQuery.getScript('/iONjsLib/js/jquery.blockUI.js',function()                    {                       
getDataCapturePopUpDetails(orgId,userId,loginTypeId);                           }
                );              
                                                                                }
                );          
                                                                                }
                );      
                                                                        }
                );  
                                                                                }
                );
                                                        }

Answer 1

ScriptEngine在完全独立的环境中运行JavaScript，无法访问您的浏览器。看起来你正试图用它在浏览器中显示某种弹出窗口;这不行。如果您需要远程控制浏览器，则需要使用其他API，而不是ScriptEngine。

Java代码中的JavaScript抛出异常

1 个答案: