Question

我没有足够的积分来发布图片，但这里是我的桌面截图的链接：My query screen shot

我有一个SQL Server表，生病和员工休假时间。我们的代码未输入2016-08-01的远期余额（已修复）。我需要从2016-07-01（19.32）获取远期余额并添加2016-06-30（6.66）的收益并减去2016-07-01至2016-07-31之间的所有收益（3,6）和1.5）并将其插入类似于第3行和第10行的新记录中，但远期余额应为13.48。

如何为所有EmployeeID编写SQL语句来执行此操作？我试图使用SUM但是没有成功。

Select Value 
From  EmployeeVacations 
Where Vacation_Kind = 'SL'
  and Vacation_Type = 'Forward' 
  and CreationDate = '2016-07-01' 
  and EmployeeId = 1775

加：

Select Value 
From  EmployeeVacations 
Where Vacation_Kind = 'SL' 
  and Vacation_Type = 'Earned' 
  and CreationDate = '2016-06-30' 
  and EmployeeId = 1775

减：

Select SUM(Value) as TotalTaken 
From  EmployeeVacations 
Where Vacation_Kind = 'SL' 
  and Vacation_Type = 'Taken' 
  and CreationDate >= '2016-07-01' 
  and CreationDate <= '2016-07-31' 
  and EmployeeId = 1775

然后从这三个值中取出值并插入新记录，如

INSERT into EmployeeVacations ([EmployeeId], [Vacation_Kind], [Vacation_Type], [CreationDate], [Value]) 
VALUES (1775, 'SL', 'Forward', '2016-08-01', 13.48)

Answer 1

我没有重现您的数据，所以我无法对此进行测试，但我认为您应该采用这样的方法：

INSERT INTO EmployeeVacations ([EmployeeId], [Vacation_Kind], [Vacation_Type], [CreationDate], [Value])
SELECT EmployeeId, 'SL', 'Forward', '2016-08-01', SUM(Value)
FROM (
    Select EmployeeId, Value 
    From  EmployeeVacations 
    Where Vacation_Kind = 'SL'
    and Vacation_Type = 'Forward' 
    and CreationDate = '2016-07-01' 

    UNION ALL

    Select EmployeeId, Value 
    From  EmployeeVacations 
    Where Vacation_Kind = 'SL' 
    and Vacation_Type = 'Earned' 
    and CreationDate = '2016-06-30' 

    UNION ALL

    Select EmployeeId, -Value
    From  EmployeeVacations 
    Where Vacation_Kind = 'SL' 
    and Vacation_Type = 'Taken' 
    and CreationDate >= '2016-07-01' 
    and CreationDate <= '2016-07-31' 
) SubQ
GROUP BY EmployeeId

正如您所看到的，我只是使用一个子查询，其中包含您需要的所有信息，而不是其他内容，然后我只是按员工对其进行分组。

当然，您应首先在没有INSERT行的情况下运行它，以确保获得所需内容。

Answer 2

尝试此查询：它应该为您提供所需的结果。首先检查一个员工，例如你的例子中的1775。然后测试另一名员工。然后在不指定任何员工ID的情况下运行（当前查询不指定任何员工ID。该部分已注释掉）。它可能需要很少的修改，但鉴于你的情况我怀疑。如果结果很好，那么你可以在插入语句中使用它，如@Andrew answer。

所示

SELECT
    EVF.EmployeeId
    ,'SL'
    ,'Forward'
    ,'2016-08-01'
    ,EVF.Value + EVE.EarnedLeave - EVT.TotalTaken AS Forward
FROM  EmployeeVacations EVF
INNER JOIN
(
    SELECT
        EmployeeId
        ,Value AS EarnedLeave
    FROM EmployeeVacations
    WHERE
        Vacation_Kind = 'SL'
        AND Vacation_Type = 'Earned'
        AND CreationDate = '2016-06-30'
) EVE ON EVE.EmployeeID = EVF.EmployeeId
INNER JOIN
(
    SELECT
        EmployeeId
        ,SUM(Value) AS TotalTaken
    FROM EmployeeVacations
    WHERE
        Vacation_Kind = 'SL'
        AND Vacation_Type = 'Taken'
        AND CreationDate >= '2016-07-01'
        AND CreationDate <= '2016-07-31'
    GROUP BY EmployeeId
) EVT ON EVT.EmployeeId = EVF.EmployeeId
WHERE
    Vacation_Kind = 'SL'
    AND Vacation_Type = 'Forward'
    AND CreationDate = '2016-07-01'
    --AND EmployeeId = 1775

将SQL值计算为新插入

2 个答案: