Question

我是Scala的新手。我正在制作游戏，我有一个角色可以访问的位置列表，类型为Location。我有一个案例类和一个伴随对象来实现这一目标。

LinkedLocations内的{p> Location是Location类型的数组，可以包含位置可以导致的任意数量的位置。在这种情况下，1号房间通向2号房间，反之亦然。

case class Location(name: String, desc: String, linkedLocations: Array[Location]){}

object Location {

  val none: Location = Location("none","none",Array(none))
  val room1: Location = Location("room 1","you are in room 1",Array(room2))
  val room2: Location = Location("room 2","you are in room 2",Array(room1))

  room1.linkedLocations.foreach(location=>println(location.name))
}

我试过让它们变得很懒，但最终会出现堆栈溢出。如何修复这样的引用问题？是否有更好的方法来设计它？

Answer 1

这看起来像图形表示 - 通常通过将图形节点（在这种情况下为位置）与图形边缘（链接位置）分离来避免前向引用。您可以通过哈希映射查找相邻信息。类似的东西：

case class Location(name: String, desc: String)

object Location {

  val none: Location = Location("none","none")
  val room1: Location = Location("room 1","you are in room 1")
  val room2: Location = Location("room 2","you are in room 2")

  val neighborMap: Map[Location, Array[Location]] = Map(
    room1 -> Array(room2),
    room2 -> Array(room1)
  )
}

然后你可以这样做：

neighborMap(room1).foreach(location => println(location.name))

Scala转发引用

1 个答案: