Question

这是我现在的整个查询，第一部分似乎很好，但从“Y as”开始，它显示所有用红色下划线的列。我用粗体标出了一个显示红色下划线的语句。我需要计算SLA的百分比，这是我无法通过此查询得出的。营业时间为周六至周日上午4:30至下午5:30，周一至周五上午4:30至晚上10:30。

SELECT
    [JOB_TICKET].[JOB_TICKET_ID],
    [JOB_TICKET].[REPORT_DATE],
    [JOB_TICKET].[FIRST_RESPONSE_DATE],
    [JOB_TICKET].CLOSE_DATE,
    ,[JOB_TICKET].LAST_UPDATED,
    [PRIORITY_TYPE].[PRIORITY_TYPE_NAME] AS 'Ticket_Priority' ,
    DATEDIFF(MINute, report_date,FIRST_RESPONSE_DATE) as 'time_to_accept' ,
    sum (CASE 
         WHEN (DATEDIFF(MINute,report_date,FIRST_RESPONSE_DATE) <= '10' )
           THEN 1 
         ELSE 0 
       END) AS "SLA time_to_accept Status",
    DATEDIFF(MINUTE,[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET].[CLOSE_DATE]) as 'time_to_resolve' ,
    (CASE 
          when PRIORITY_TYPE_NAME='low' 
            then sum(case 
                       when DATEDIFF(MINUTE,[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET].[CLOSE_DATE]) <= '960' 
                         then 1 
                         else 0 
                       end ) 
          when PRIORITY_TYPE_NAME='medium' 
            then sum(case 
                       when DATEDIFF(MINUTE[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET].[CLOSE_DATE]) <= '480' 
                         then 1  
                         else 0 
                       end )  
          when PRIORITY_TYPE_NAME='high' 
            then sum(case
                        when DATEDIFF(MINUTE,[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET]. [CLOSE_DATE]) <= '120' 
                          then 1  
                          else 0 
                        end )
          when PRIORITY_TYPE_NAME='Urgent' 
            then sum(case 
                        when DATEDIFF(MINUTE,[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET].  [CLOSE_DATE]) <= '60' 
                          then 1 
                          else 0   
                        end)   
          end) as "Closed within SLA"  FROM [SWHD01].[dbo].[JOB_TICKET] INNER JOIN [SWHD01].[dbo].[STATUS_TYPE] ON [JOB_TICKET].[STATUS_TYPE_ID] =[STATUS_TYPE].[STATUS_TYPE_ID] INNER JOIN [SWHD01].[dbo].[PROBLEM_TYPE] ON [JOB_TICKET].[PROBLEM_TYPE_ID] = [PROBLEM_TYPE].[PROBLEM_TYPE_ID]  INNER JOIN [SWHD01].[dbo].[PRIORITY_TYPE] ON [JOB_TICKET].[PRIORITY_TYPE_ID] = [PRIORITY_TYPE].[PRIORITY_TYPE_ID] where REPORT_DATE is not null and DATEDIFF(MINUTE,[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET].[CLOSE_DATE]) is not null and DATEDIFF(MINUTE,[JOB_TICKET].[FIRST_RESPONSE_DATE],[JOB_TICKET].[CLOSE_DATE]) > 0 group by JOB_TICKET_ID,[JOB_TICKET].[REPORT_DATE],[JOB_TICKET].[FIRST_RESPONSE_DATE],
  [JOB_TICKET].CLOSE_DATE,[JOB_TICKET].LAST_UPDATED,[PRIORITY_TYPE].[PRIORITY_TYPE_NAME]

Answer 1

由于您需要重复使用time_to_accept和time_to_resolve，因此请使用CTE，这样您就不必重复这些长DATEDIFF个表达式。
使用另一个CTE，因此您不必重复长CASE个表达式 time_to_accept and time_to_resolve。
最后，你完全没了来自您的主要FROM的{{1}}声明;我添加了SELECT作为占位符。

FROM SomeTable

如何比较从select创建的临时列以计算SLA？

1 个答案: