Question

我有一个JSON响应如下

{
  ......,

  "phoneNumbers":[
   {
    "info":[

  ],
  "phoneNumber":"1234567890",
  "phoneNumberType":"HOME_NUMBER"
 },
 {
  "info":[

  ],
  "phoneNumber":"9876543210",
  "phoneNumberType":"WORK_NUMBER"
 },
 {
  "info":[

  ],
  "phoneNumber":"7418529630",
  "phoneNumberType":"MOBILE_NUMBER"
 }
],

.......

}

我需要提取手机号码，我试试这个

  val jsonBody = Json.parse(phoneListResponse.body)
  val phoneList: Seq[JsValue] = (jsonBody \\ "phoneNumbers")
  val mobileNodes: Seq[JsValue] = phoneList.filter(number => {
   (number \\ "phoneNumberType").head.asInstanceOf[JsString].value == "MOBILE_NUMBER"
  })
  (mobileNodes.head \\ "phoneNumber").head.asInstanceOf[JsString].value

但是我的mobileNodes是空的。有什么建议吗？

Answer 1

如果您使用Play-json

val phoneList: Seq[String] = 
 ((jsonBody \\ "phoneNumbers")(0).as[List[JsValue]])
 .filter(x => (x \ "phoneNumberType").as[String] == "MOBILE_NUMBER")
 .map(x => (x \ "phoneNumber").as[String])

REPL输出

scala>  ((json \\ "phoneNumbers")(0).as[List[JsValue]]).foreach(println)
{"info":[],"phoneNumber":"1234567890","phoneNumberType":"HOME_NUMBER"}
{"info":[],"phoneNumber":"9876543210","phoneNumberType":"WORK_NUMBER"}
{"info":[],"phoneNumber":"7418529630","phoneNumberType":"MOBILE_NUMBER"}

scala>  ((json \\ "phoneNumbers")(0).as[List[JsValue]]).filter(x => (x \ "phoneNumberType").as[String] == "MOBILE_NUMBER")
res31: List[play.api.libs.json.JsValue] = List({"info":[],"phoneNumber":"7418529630","phoneNumberType":"MOBILE_NUMBER"})

scala>  ((json \\ "phoneNumbers")(0).as[List[JsValue]]).filter(x => (x \ "phoneNumberType").as[String] == "MOBILE_NUMBER").map(x => (x \ "phoneNumber").as[String])
res32: List[String] = List(7418529630)

使用ScalaJson从JSON字符串Scala读取值

1 个答案: