我有一个奇怪的问题..当我加载我的详细信息页面时,错误部分首先在控制器中执行。
虽然服务myService
被执行并且它确实返回了值,但是在控制器中执行错误并且我没有收到我的消息详细信息。
我之前已提供警报,且jsonObj
有效。
控制器:
url = 'http://' + add + ':8080/user/site.cgi';
data = {
ACTION : "list",
STATS : "no"
};
myService.getdata(url, data)
.then(function(data, status, headers, config) {
$timeout(function(){
if (data.body.response.status == "OK") {
if (data.body.response.msg.id) {
service2.seturl(data.body.response.msg.id, username, add);
messg.push(data.body.response.msg);
} else
angular.forEach(data.body.response.msg, function(value, key) {
service2.seturl(value.id, username, add);
messg.push(value);
})
$rootScope.messg = messg;
} else {
errorMessage = data.body.response.errmsg;
alert(errorMessage);
}
}, 5000);
}, function(error, status, headers, config) {
alert("Check network connection.."); //Coming here without fulfilling promise.
});
}
服务:
.service('myService', function($http, $q, $httpParamSerializerJQLike) {
return {
getdata: function(url, data) {
var postData = data;
return $http({
method : 'POST',
url : url,
data : $httpParamSerializerJQLike(postData)
}).then(function(response, status, headers, config) {
var x2js = new X2JS();
var jsonObj = x2js.xml_str2json(response.data);
if (typeof jsonObj === 'object') {
alert(jsonObj); //I am getting this alert just fine.
return jsonObj; //It does return the object.
} else {
return $q.reject(jsonObj);
}
}, function(response, status, headers, config) {
return $q.reject(response.data);
});
}
}
})
.factory('service2', function() {
var urls = [{ }];
return {
all: function() {
return urls;
},
geturl: function(id) {
for (var i = 0; i < urls.length; i++) {
if (urls[i].id === parseInt(id)) {
return urls[i];
}
}
return null;
},
seturl: function(id, admin, add) {
for (var i = 0; i < urls.length; i++) {
if (urls[i].id === parseInt(id)) {
return null;
}
}
var idInt = parseInt(id);
var createurl = 'http://' + add + ':8080/user/det.cgi';
var postData = {
ACTION : “add”,
LOGIN : admin
};
var url = {
id: idInt,
url: createurl,
data: postData
}
urls.push(url);
return null;
}
};
})
答案 0 :(得分:0)
试试这个,返回一个延期的承诺
.service('myService', function($http, $q, $httpParamSerializerJQLike) {
return {
getdata: function(url, data) {
var deferred = $q.defer();
var postData = data;
$http({
method : 'POST',
url : url,
data : $httpParamSerializerJQLike(postData)
}).then(function(response, status, headers, config) {
var x2js = new X2JS();
var jsonObj = x2js.xml_str2json(response.data);
if (typeof jsonObj === 'object') {
alert(jsonObj);
deferred.resolve(jsonObj);
} else {
deferred.reject(jsonObj);
}
}, function(response, status, headers, config) {
deferred.reject(response.data);
});
return deferred.promise;
}
} })