Question

我正在我指定的目录中创建一个文件。我想为每次运行在不同文件名的目录中创建不同的文件夹名称。这个文件夹应该压缩。

目前我正在使用：

create or replace
PROCEDURE xx_WriteBLOBToFILE (myfilename IN VARCHAR2,L_PERSON_ID IN NUMBER) IS 

  v_blob         BLOB;
  blob_length    INTEGER;
    out_file utl_file.file_type;
  v_buffer       RAW(32767);
  chunk_size     BINARY_INTEGER := 32767;
  blob_position  INTEGER := 1;

BEGIN

  -- Retrieve the BLOB for reading
  Select Image Into V_Blob From Per_Images 
  Where Parent_Id =L_PERSON_ID;

  -- Retrieve the SIZE of the BLOB
  blob_length:=DBMS_LOB.GETLENGTH(v_blob);

  -- Open a handle to the location where you are going to write the BLOB to file
  -- NOTE: The 'wb' parameter means "write in byte mode" and is only availabe
  --       in the UTL_FILE package with Oracle 10g or later
  out_file := UTL_FILE.FOPEN ('INTF_DIR1', myfilename, 'wb', chunk_size);

  -- Write the BLOB to file in chunks 
  WHILE blob_position <= blob_length LOOP
    IF blob_position + chunk_size - 1 > blob_length THEN
      chunk_size := blob_length - blob_position + 1;
    END IF;
    DBMS_LOB.READ(v_blob, chunk_size, blob_position, v_buffer);
    UTL_FILE.PUT_RAW(out_file, v_buffer, TRUE);
    blob_position := blob_position + chunk_size;
  END LOOP;

  -- Close the file handle
  UTL_FILE.FCLOSE (out_file);
END;

这段代码正在将blob图像移动到目录中的文件夹中。我想要在一个单独的文件夹中生成这个blob图像，该文件夹将位于压缩文件夹下

Answer 1

在本次讨论结束时，请参阅az_zip包的链接 Zip using Oracle Stored Procedure

https://technology.amis.nl/wp-content/uploads/2010/06/as_zip10.txt

如何在plsql（Oracle）中创建zip文件夹

1 个答案: