Question

在尝试解决this计算机奥林匹克问题时，我遇到了这个错误：

Traceback (most recent call last):
File "haybales.py", line 5, in <module>
    s = input()
File "<string>", line 0

^
SyntaxError: unexpected EOF while parsing

我目前的代码如下：

hay = []
s = input()
while s != 'END':
    hay.append(s)
    s = input()

    for i in hay: #adds all integers in array
        var = var + i

       if var % hay[0] == 0:
            average = var / hay[0] #finds average of all numbers in array

            for bale in hay:
                diff = bale - average
                total += diff 
                #finds sum of all differences to find the final answer

             print 'you need to move' + str(total) + 'piles of hay'

        else:
            print 'it\'s not possible to make them equal'

我的输入是否被错误地读取？如何更改代码以解决错误？

Answer 1

除了Andrew Hewitt建议的修补程序之外，您看到的错误是由于您在python2中使用input而不是raw_input（在python3 raw_input中）重命名为{{ 1}}）。如果您检查input的{{3}}，您会发现它需要有效的python代码，然后尝试运行它并返回其中的内容。 input只会将您的输入放在一个字符串中并将其返回。

所以只需使用raw_input并手动将您获得的字符串转换为所需的格式。

Answer 2

您的代码存在许多问题：

<强>压痕：在Python中缩进非常重要。您不能忽略它，否则您的代码将无法运行或产生意外结果。这可能是由于你将代码粘贴到堆栈溢出的方式，我承认这有时会很麻烦，但最好提一下以防万一。

hay = []
s = input()
while s != 'END':
    hay.append(s)
    s = input()

for i in hay: #adds all integers in array
    var = var + i

if var % hay[0] == 0:
    average = var / hay[0] #finds average of all numbers in array

    for bale in hay:
        diff = bale - average
        total += diff
        #finds sum of all differences to find the final answer

    print 'you need to move' + str(total) + 'piles of hay'

else:
    print "it's not possible to make them equal"

<强>输入：您应该将输入转换为整数以允许calucation正常运行。理想情况下，您也会验证输入，但这是另一个主题。在这里，只需更改第4行：
```
hay.append(int(s))
```

<强>范围：变量的可见性在您的代码中有点偏差。例如，在第8行，您尝试向var添加值。但是每次运行循环时var都是一个新变量，会导致错误。（var未定义）。这对Total来说也是一个问题。

hay = []
s = input()
while s != 'END':
    hay.append(s)
    s = input()

var = 0 ###ADD var HERE
for i in hay: #adds all integers in array
    var = var + i

if var % hay[0] == 0:
    average = var / hay[0] #finds average of all numbers in array

    total = 0 ###ADD total HERE
    for bale in hay:
        diff = bale - average
        total += diff
        #finds sum of all differences to find the final answer

    print 'you need to move' + str(total) + 'piles of hay'

else:
    print "it's not possible to make them equal"

<强>计算：平均值是所有值的总和除以值的数量。 hay [0]是第一个值，而不是值的数量。要获取输入的值的数量，可以使用len（）函数。

hay = []
s = input()
while s != 'END':
    hay.append(s)
    s = input()

var = 0;
for i in hay: #adds all integers in array
    var = var + i

if var % hay[0] == 0:
    ###CHANGE BELOW LINE TO USE len(hay)
    average = var / len(hay) #finds average of all numbers in array

    total = 0
    for bale in hay:
        diff = bale - average
        total += diff
        #finds sum of all differences to find the final answer

    print 'you need to move' + str(total) + 'piles of hay'

else:
    print "it's not possible to make them equal"

打印：打印时请记住在连接（连接）字符串之前和之后添加空格：

print 'you need to move ' + str(total) + ' piles of hay'

否则输出时将没有空间。

我希望这会有所帮助。

语法错误：解析时出现意外的EOF。我输错了吗？

2 个答案: