Construct(T const& )
我想按规则输出
ID tag index
001 1 fsklgg
001 2 segwrh
001 3 esfjkg
002 4 seggrg
002 5 gehewv
002 6 egwgsg
003 1 esgges
003 4 yjkdsa
003 9 wrfsbb
像这样
1. each ID will only have one output
2. the output will be sort by "tag" which is the largest
但我的回答总是
ID tag index
001 3 esfjkg
002 6 egwgsg
003 9 wrfsbb
我使用GROUP BY标签,但答案是最小的。 我试图使用ORDER BY DESC,希望答案会改变,但它不起作用。 任何人都可以教我如何处理答案吗? 或者我应该使用什么命令?
我的源代码是
ID tag index
001 1 fsklgg
002 4 seggrg
003 1 esgges
使用MariaDB
答案 0 :(得分:2)
//Pressed start
I/System.out: Starting counter!
I/System.out: RUNNING
I/System.out: 0
I/System.out: 1
I/System.out: 2
I/System.out: 3
I/System.out: 4
I/System.out: 5
I/System.out: 6
//Pressed stop
I/System.out: Stopping counter!
I/System.out: PENDING
//Pressed start
I/System.out: Starting counter!
I/System.out: RUNNING
//Pressed stop
I/System.out: Stopping counter!
I/System.out: PENDING
使用子查询:
SELECT t1.ID,
t1.tag,
t1.index
FROM yourTable t1
INNER JOIN
(
SELECT ID, MAX(tag) AS tag
FROM yourTable
GROUP BY ID
) t2
ON t1.ID = t2.ID AND
t1.tag = t2.tag
ORDER BY t1.tag
答案 1 :(得分:1)
试试这个:
SELECT a.*
FROM tableA a
WHERE EXISTS(
SELECT ID, tag FROM (
SELECT ID, MAX(tag) tag FROM tableA GROUP BY ID) t
WHERE t.id = a.id AND t.tag = a.tag)
ORDER BY a.tag DESC