如何使用正则表达式匹配字符串中的单词

Question

我有一个像这样的字符串

test = "row-even row-dd testing"

现在我想只得到以row-开头的单词。

我用过test =〜/ year-（。*）/ 但它一直让我回归0.anyidea我怎么能这样做？

Answer 1

r = /
    (?<=\A|\s)   # match start of string or space in a positive lookbehind
    row-         # match string 'row-'
    [[:alpha:]]+ # match one or more letters
    (?=\s|\z)    # match a space or end of string in a positive lookahead
    /x           # free-spacing regex definition mode

"row-even row-dd testing".scan(r)    #=> ["row-even", "row-dd"]
"borrow-even row-dd testing".scan(r) #=> ["row-dd"]
"row-even row-dd1 testing".scan(r)   #=> ["row-even"]

Answer 2

0是找到的模式的起始位置。

请改为尝试：

puts test.scan(/row-\w+/)