我有一个ANT目标,在相同的源代码上运行两次findbugs以生成xml和html报告
<delete dir="${findbugs.dir}"/>
<mkdir dir="${findbugs.dir}"/>
<findbugs
home="${findbugs.home}"
output="xml"
outputFile="${findbugs.dir}/findbugs.xml"
jvmargs="${findbugs.jvmargs}"
timeout="${findbugs.timeout}"
effort="${findbugs.effort}">
<sourcePath path="${src.dir}"/>
<class location="${build.classes.dir}"/>
</findbugs>
<findbugs
home="${findbugs.home}"
output="html"
outputFile="${findbugs.dir}/findbugs.html"
jvmargs="${findbugs.jvmargs}"
timeout="${findbugs.timeout}"
effort="${findbugs.effort}">
<sourcePath path="${src.dir}"/>
<class location="${build.classes.dir}"/>
</findbugs>
这很愚蠢,因为可以使用
从xml报告生成html报告<xslt in="${findbugs.dir}/findbugs.xml" out="${findbugs.dir}/findbugs.html" style="${findbugs.home}/default.xsl"/>
但生成的html报告没有正确的源代码引用。有关如何使其工作并避免重复的findbugs调用的任何想法?
回答后更新
with output="xml"
<BugInstance type="REC_CATCH_EXCEPTION" priority="2" abbrev="REC" category="STYLE">
<Class classname="com.x.y.aggregate.AggregationProperties">
<SourceLine classname="com.x.y.aggregate.AggregationProperties" start="20" end="788" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java"/>
</Class>
<Method classname="com.x.y.aggregate.AggregationProperties" name="setAggregateProperties" signature="()V" isStatic="true">
<SourceLine classname="com.x.y.aggregate.AggregationProperties" start="86" end="148" startBytecode="0" endBytecode="489" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java"/>
</Method>
<SourceLine classname="com.x.y.aggregate.AggregationProperties" start="140" end="140" startBytecode="308" endBytecode="308" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java"/>
</BugInstance>
with 'xml:withMessages'
<BugInstance type="REC_CATCH_EXCEPTION" priority="2" abbrev="REC" category="STYLE" instanceHash="b7a7c8f292d2a8432680a1c971fb93b3" instanceOccurrenceNum="0" instanceOccurrenceMax="0">
<ShortMessage>Exception is caught when Exception is not thrown</ShortMessage>
<LongMessage>Exception is caught when Exception is not thrown in com.x.y.aggregate.AggregationProperties.setAggregateProperties()</LongMessage>
<Class classname="com.x.y.aggregate.AggregationProperties" primary="true">
<SourceLine classname="com.x.y.aggregate.AggregationProperties" start="20" end="788" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java" relSourcepath="com/x/y/aggregate/AggregationProperties.java">
<Message>At AggregationProperties.java:[lines 20-788]</Message>
</SourceLine>
<Message>In class com.x.y.aggregate.AggregationProperties</Message>
</Class>
<Method classname="com.x.y.aggregate.AggregationProperties" name="setAggregateProperties" signature="()V" isStatic="true" primary="true">
<SourceLine classname="com.x.y.aggregate.AggregationProperties" start="86" end="148" startBytecode="0" endBytecode="489" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java" relSourcepath="com/x/y/aggregate/AggregationProperties.java"/>
<Message>In method com.x.y.aggregate.AggregationProperties.setAggregateProperties()</Message>
</Method>
<SourceLine classname="com.x.y.aggregate.AggregationProperties" primary="true" start="140" end="140" startBytecode="308" endBytecode="308" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java" relSourcepath="com/x/y/aggregate/AggregationProperties.java">
<Message>At AggregationProperties.java:[line 140]</Message>
</SourceLine>
</BugInstance>
答案 0 :(得分:2)
output="xml:withMessages"
如果设置为“xml”(默认值),则输出为XML格式。如果设置为“xml:withMessages”,则输出为XML格式,并使用人类可读的消息进行扩充。 (如果您计划使用XSL样式表生成报告,则应使用此格式。)