尝试打印Json键值但索引正在打印

Question

预期输出应打印键及其值

var myData = '{"is_bot":"No","device":"desktop","brand":"Sony","brand_model":"Vaio","os":"GNU\/Linux","os_version":"15.5","browser":"Chrome","browser_version":"52.0","ua_string":"Mozilla\/5.0 (X11; Linux x86_64) AppleWebKit\/537.36 (KHTML, like Gecko) Chrome\/52.0.2743.82 Safari\/537.36"}'
    for (var key in myData) {
       console.log(' name=' + key + ' value=' + myData[key]);
    }

然而，控制台正在打印

感谢帮助

Answer 1

首先使用JSON.parse(str)

将字符串解析为JSON

var myData = '{"is_bot":"No","device":"desktop","brand":"Sony","brand_model":"Vaio","os":"GNU\/Linux","os_version":"15.5","browser":"Chrome","browser_version":"52.0","ua_string":"Mozilla\/5.0 (X11; Linux x86_64) AppleWebKit\/537.36 (KHTML, like Gecko) Chrome\/52.0.2743.82 Safari\/537.36"}';

   myData = JSON.parse(myData);

    for (var key in myData) {
       console.log(' name=' + key + ' value=' + myData[key]);
    }

Answer 2

您需要将字符串解析为实际的javascript对象。您看到的结果是因为您正在迭代字符串。

＆＃13;

＆＃13;

var raw = '{"is_bot":"No","device":"desktop","brand":"Sony","brand_model":"Vaio","os":"GNU\/Linux","os_version":"15.5","browser":"Chrome","browser_version":"52.0","ua_string":"Mozilla\/5.0 (X11; Linux x86_64) AppleWebKit\/537.36 (KHTML, like Gecko) Chrome\/52.0.2743.82 Safari\/537.36"}';

var data = JSON.parse(raw);

for (var key in data) {
    console.log(' name=' + key + ' value=' + data[key]);
}

＆＃13;

＆＃13;

＆＃13;

Answer 3

关键是将JSON作为字符串读取 - 您需要从中删除单引号'以使其成为Ojbect

像这样：

var myData = {"is_bot":"No","device":"desktop","brand":"Sony","brand_model":"Vaio","os":"GNU\/Linux","os_version":"15.5","browser":"Chrome","browser_version":"52.0","ua_string":"Mozilla\/5.0 (X11; Linux x86_64) AppleWebKit\/537.36 (KHTML, like Gecko) Chrome\/52.0.2743.82 Safari\/537.36"}

Answer 4

您正在迭代字符串中的每个字符，因为这是一个字符串而不是对象。

 var myData = JSON.parse(myData);

 Object.keys(myData).forEach(function(key) {
    console.log(' name=' + key + ' value=' + myData[key]); 
 });

有关Object.keys的详情，请查看this link