从表A
| id |col1 | col2 | col3|
--------------------------
| 1 | a | x1 | y1 |
--------------------------
| 2 | b | x2 | y2 |
--------------------------
| 3 | c | x3 | y3 |
--------------------------
至表B
| id |x_a | y_a | x_b | y_b | x_c | y_c |
------------------------------------------
| 1 | x1 | y1 | x2 | y2 | x3 | y3 |
------------------------------------------
感谢
答案 0 :(得分:0)
您的PLSQL代码如下:
declare
var varchar2(4000):= NULL;
var1 varchar2(4000):= NULL;
begin
for i in (select * from tabA where id = 1)
loop
dbms_output.put_line('| id |x_a | y_a | x_b | y_b | x_c | y_c |');
dbms_output.put_line('-------------------------------------------');
for j in (select col2,col3 from tabA)
loop
var1:= j.col2 ||' | '|| j.col3||' | ';
var:= var ||var1;
end loop;
dbms_output.put_line('|'|| i.id ||' | '|| var);
var:=NULL;
end loop;
end;
,输出为:
| id |x_a | y_a | x_b | y_b | x_c | y_c |
-------------------------------------------
|1 | x1 | y1 | x2 | y2 | x3 | y3 |