Question

我制作了一个java控制台程序，它打印输入的二进制值的十进制值。现在，我的程序存在问题

例如输出：输入input = 10011101，然后二进制值为3534200而不是157

在浏览互联网以获取将二进制值转换为十进制的公式后，这是我制作此程序时的参考。

1 * 2 ^ 7 + 0 * 2 ^ 6 + 0 * 2 ^ 5 + 1 * 2 ^ 4 + 1 * 2 ^ 3 + 1 * 2 ^ 2 + 0 * 2 ^ 1 + 1 * 2 ^ 0 = 157。

我尝试使用长版本制作这个程序，使用for循环...我觉得这是一个愚蠢的挑战？哈哈！

这里是代码（带评论！）：

byte binary[] = new byte[127];   //declared a byte array for input value
int power = 2, formula = 0;      //declared the power and the formula as int
System.out.print("Enter Binary: "); //prints "Enter binary:"
System.in.read(binary);          //inserts the input in the binary array
Integer bin = Integer.parseInt(new String(binary).trim()); //converts the input value to int for another conversion
String b = Integer.toString(bin); //converts the int bin to string
Integer num = Integer.parseInt(new String(b.substring(b.length() - 1).trim())); 
//num variable gets the value of last string (should be anyway)
System.out.println("The Decimal Value of " + bin + " is ");
for(int i = b.length(); i > 0; i--){ 
    for(int a = i; a > 0; a--){ //the condition
        power = power*2;        //as the loop goes, if 2^3 then it should be 8
    }
    formula = formula + (num * (power)); //as the given formula above, this is what I did
    System.out.println("power: " + power);//if you want reference, I left it here
    System.out.println("formula: " +formula);
    System.out.println("num: " + num);

    num = Integer.parseInt(new String(b.substring(i - 1).trim())); //uhm dunno how to describe this, but you'll see
    power = 2;
}
System.out.print(formula);

} }

自从我开始使用java以来，这是我所知道的唯一事情。（请参阅自第4章以来的最后一个问题）

请帮助:(

Answer 1

你有很多问题：

1）Integer.parseInt(new String(binary).trim())不符合你的想法。因此，你的数字是错误的。

2）你计算错误的力量。

3）一般建议，用一些空行将代码分成有意义的小块。它的眼睛会更容易。

固定程序应如下所示：

public static void main(String[] args) throws IOException {
    byte binary[] = new byte[127];   //declared a byte array for input value
    int power = 2, formula = 0;      //declared the power and the formula as int

    System.out.print("Enter Binary: "); //prints "Enter binary:"
    System.in.read(binary);          //inserts the input in the binary array
    Integer bin = Integer.parseInt(new String(binary).trim()); //converts the input value to int for another conversion

    String b = Integer.toString(bin); //converts the int bin to string
    Integer num; //num variable gets the value of last string (should be anyway)
    System.out.println("The Decimal Value of " + bin + " is ");

    for(int i = b.length(); i > 0; i--){ 
        power = 1;
        num = Integer.parseInt(Character.toString(b.charAt(i-1)));

        for(int a = i; a < b.length(); a++){ //the condition
            power = power*2;        //as the loop goes, if 2^3 then it should be 8
        }

        formula = formula + (num * (power)); //as the given formula above, this is what I did
        System.out.println("power: " + power);//if you want reference, I left it here
        System.out.println("formula: " +formula);
        System.out.println("num: " + num);
    }
    System.out.print(formula);
}

一个转换＆＃34; BINARY＆＃34;的Java控制台程序到＆＃34; DECIMAL＆＃34;不使用for循环的预定义方法

1 个答案: