Question

我需要按层次顺序列出我的数据库的所有表（PostgreSQL）。这意味着：如果表“user”有一个外键来表“角色”，那么它必须在列表中的“角色”之后。

等同于：

EXEC sp_msdependencies @intrans = 1

在SQL Server中。

我试过了，但没有成功：

SELECT
    pt.table_name as tablename,
    string_agg(DISTINCT ccu.table_name, ',') AS reftable
FROM information_schema.tables pt
LEFT JOIN information_schema.columns c
    ON c.table_name = pt.table_name
LEFT JOIN information_schema.table_constraints tc
    ON tc.table_name = pt.table_name AND tc.constraint_type = 'FOREIGN KEY'
LEFT JOIN information_schema.key_column_usage AS kcu
    ON tc.constraint_name = kcu.constraint_name AND kcu.column_name = c.column_name
LEFT JOIN information_schema.constraint_column_usage AS ccu
    ON ccu.constraint_name = tc.constraint_name
WHERE pt.table_schema = 'public'
GROUP BY pt.table_name,pt.table_type
ORDER BY pt.table_type DESC, COUNT(TRUE) ASC;

Answer 1

我认为你不能用一个简单的SELECT做到这一点。您可能需要递归查询。

information_schema似乎特别不适合这种情况，因为它假设约束名称在模式中是唯一的，这是Postgres不强制执行的。换句话说，如果您有两个具有相同名称的约束，我认为在constraint_column_usage中没有任何方法可以区分它们。所以你最好使用Postgres自己的目录。

这似乎有效，但我还没有彻底测试过：

WITH RECURSIVE ref (tbl, reftbl, depth) AS (
  SELECT pg_class.oid, NULL::oid, 0
  FROM pg_class
  JOIN pg_namespace ON
    pg_namespace.oid = pg_class.relnamespace
  WHERE 
    relkind = 'r' AND
    nspname = 'public' AND
    NOT EXISTS (
      SELECT 1 FROM pg_constraint
      WHERE 
        conrelid = pg_class.oid AND
        contype = 'f'
    )
  UNION ALL
  SELECT conrelid, ref.tbl, ref.depth + 1
  FROM ref
  JOIN pg_constraint ON
    confrelid = ref.tbl AND
    contype = 'f'
)
SELECT
  tbl::regclass::text as tablename,
  string_agg(DISTINCT reftbl::regclass::text, ',') as reftables
FROM ref
GROUP BY tablename
ORDER BY max(depth)

PostgreSQL - 所有表的分层列表

1 个答案: