Question

我正在运行一个小循环，将一个数字列表（1到30）随机分配给4个组的子集。我想将循环的输出（对于4个子集）作为一行存储在一个变量中，并在其他地方使用结果。我也收到一些警告，但输出正确显示在屏幕上。

list = as.vector(c(6, 9, 3, 12)
start <- 1
end <- 6
i <- 1
while(i<=list){
  print(sample(start:end, replace=T))
  start <- start+list[i]
  end <- end + list[i+1]
  i <- i+1
}

[1] 3 5 6 1 5 6
[1]  9 13 12  7 11 12 14 11 14
[1] 16 17 17
 [1] 28 22 26 21 28 26 22 28 26 30 21 19
Error in start:end : NA/NaN argument
In addition: Warning messages:
1: In while (i <= list) { :
  the condition has length > 1 and only the first element will be used
2: In while (i <= list) { :
  the condition has length > 1 and only the first element will be used
3: In while (i <= list) { :
  the condition has length > 1 and only the first element will be used
4: In while (i <= list) { :
  the condition has length > 1 and only the first element will be used
5: In while (i <= list) { :
  the condition has length > 1 and only the first element will be used

我无法找到此错误的原因。请帮忙。谢谢。

Answer 1

使用for循环比使用while循环更好，当我们使用seq函数时不需要子变量i变量

// and you need a %n on the end to make 3 lines.
System.err.format("1st Line %nPrints At 3rd Line,Shouldn't this be In 2nd Line%n"); 
System.err.flush(); // <-- only needed if the previous write doesn't have
                    //     an implicit flush(); newline (%n) does.
System.out.println("Shouldn't this be the third line,prints at 2nd line");

将循环的输出存储为R中的列表

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