Question

我正在尝试从本地计算机上读取Json（文本）文件，并通过Jersey＆amp; amp; AngularJs。

Web.xml中

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xmlns="http://java.sun.com/xml/ns/javaee" 
         xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
         version="3.0">

    <display-name>Your REST end Point</display-name>

    <servlet>
        <servlet-name>MyRESTEndPoint</servlet-name>
        <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>


        <init-param>
            <param-name>com.sun.jersey.config.property.packages</param-name>
            <param-value>org.itc</param-value>
        </init-param>

        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>MyRESTEndPoint</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
    </welcome-file-list>

</web-app>

Controller.java

@Path("/")
public class Controller {

    @GET
    @Path("/receive")
    @Consumes(MediaType.APPLICATION_JSON)
    @Produces(MediaType.APPLICATION_JSON)
    public JSONObject crunchifyREST(int a) throws FileNotFoundException {

        System.out.println("Value received from User is:   "+a);

        String string = "";
        InputStream crunchifyInputStream = new FileInputStream("C:/abc.txt");
        InputStreamReader crunchifyReader = new           InputStreamReader(crunchifyInputStream);
        BufferedReader br = new BufferedReader(crunchifyReader);

        String line;

        try {
                while ((line = br.readLine()) != null) {
                string += line + "\n";
        }
        } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

       JSONObject jsonObject = null;
       try {
        jsonObject = new JSONObject(string);
       } catch (JSONException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    return jsonObject;
    }    
}

Controller.js

var app = angular.module('myApp', []); 
app.controller('myController',[ '$scope', '$http', function($scope, $http){

    $scope.myFunc = function() {
    var d=$scope.num;
    $http.get('receive',d ).success(function(dataTable)                   
            {   
                $scope.result = dataTable;

            }).error(function(error)
                {
                console.log(error);
                  });
    }
}]);

的index.html

<!DOCTYPE html>
<html>
    <head>
        <meta charset="ISO-8859-1">
        <title>Task</title>
        <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.5.6/angular.min.js">      </script>
        <script type="text/javascript" src="Controller.js"></script>
    </head>
    <body>
        <div data-ng-app="myApp" data-ng-controller="myController">
            <form id="loginForm" class="form-group" >
                <input type=number data-ng-model="num">
                <button type="submit" class="btn btn-sm btn-success" data-ng-click="myFunc()" >Submit</button>
                <h1>{{ result.name }}</h1>
            </form>
        </div>
    </body>
</html>

我已经包含以下罐子 -

asm-all-3.3.1
jersey-core-1.17.1
jersey-server-1.17.1
jersey-servlet-1.17.1
jersey-json-1.17.1
jersey-bundle-1.17.1
json-20090211

从HTML我只是将一个虚拟数字作为参数传递给$ http。但我得到415不支持的媒体类型。在调试模式下，我可以看到Json文本文件已从系统中读取，并且无法发送该响应。任何帮助？

Answer 1

首先，@Consumes注释用于指定发送请求正文的POST请求的application/contentType标题，因此您在GET请求中并不真正需要它。 / p>

其次，您似乎正在尝试使用Path参数，但是您没有使用正确的语法。

尝试使用您的控制器：

@Path("/")
public class Controller {

    @GET
    @Path("/receive/{a}")
    @Produces(MediaType.APPLICATION_JSON)
    public JSONObject crunchifyREST(@PathParam("a") int a) throws FileNotFoundException {

        System.out.println("Value received from User is:   "+a);

        String string = "";
        InputStream crunchifyInputStream = new FileInputStream("C:/abc.txt");
        InputStreamReader crunchifyReader = new           InputStreamReader(crunchifyInputStream);
        BufferedReader br = new BufferedReader(crunchifyReader);

        String line;

        try {
                while ((line = br.readLine()) != null) {
                string += line + "\n";
        }
        } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

       JSONObject jsonObject = null;
       try {
        jsonObject = new JSONObject(string);
       } catch (JSONException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    return jsonObject;
    }    
}

或者，您可以使用Query参数。

Answer 2

您需要在请求标头中将Content-Type设置为application / json。您的服务器不了解您的要求？如果有效，请尝试以下。

    var app = angular.module('myApp', []); 
    app.controller('myController',[ '$scope', '$http', function($scope, $http){

         $scope.myFunc = function() {
         var d=$scope.num;
         $http({
           url: 'receive', 
           method: 'GET', 
           data: d, 
           headers: {'Content-Type': 'application/json'}
          }).then(function (dataTable) {
             $scope.result = dataTable;
          }).error(function (error) {
             console.log(error);
          });
        }
    }]);

如何在Jersey + AngularJs中解决415不支持的媒体类型错误

2 个答案: