Question

它适用于localhost但不适用于服务器I.另一个警告是主线程上的同步XMLHttpRequest由于其对最终用户体验的不利影响而被弃用。如需更多帮助，请查看...

这是我的表格：

<form action ="" method="post" id="frmlogin" class="text" onsubmit="return flogin();">
    <input type="text" name="user" id="email" placeholder="Username*" required>
    <input type="password" name="pass" id="password"  placeholder="Password*" required>
    <input type="submit" name="login" class="login loginmodal-submit" value="Login">

这是我的Javascript：

<script>
    function flogin() {


        $("#errorlog").html("");

        var email = document.getElementById('email').value;
        var password = document.getElementById('password').value;

        var request = $.ajax({
            type: 'post',
            url: 'action/login_action.php',
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            data: {email: email, password: password, login: "login"},

            success: function (response) {
                var res = parseInt(response.trim());
                alert(response);
                if (response.trim() == "10") {
                    $("#errorlog").html("Email and Password is must");
                    //alert(response);

                }
                else if (res >= 1) {
                    //alert(response);
                    document.getElementById('email').value = "";
                    document.getElementById('password').value = "";
                    window.location = "index.php";
                }
                else {
                    $("#errorlog").html("E-mail  or Password is incorrect");
                }
            }, error: function (response) {
                alert("FAIL");
                alert(response);
                //alert(response[0]);
                //response is json you need to parse it
                // var json = response,

                // obj = JSON.parse(json);
                //  alert(response.length);
                //  alert(response.length);
            }
        });
        return false;
    }
</script>

php代码：

<?php
error_reporting(1);
if (!isset($_SESSION)) {
    session_start();
}
require_once("../config/encrypt.php");
require_once '../config/functions.inc';
require_once '../config/database.php';
///////////////login check////////////

if ($_POST['login'] == "login") {
    echo "fdgdffdf";
    if (empty($_POST['password']) or empty($_POST['email'])) {
        echo "10";
        exit;
    } else {
        $en = new Encryption();

        $password = trim($_POST['password']);
        $email = $en->removeBadChars(trim($_POST['email']));

        $db = new Database();
        if ($db->open())
            $password = sha1($password);
        {
            $sql = "select * from  phpap105_signup where email='$email' and password='$password'";
            // echo "select * from  phpap105_signup where email='$email' and password='$password'";
            //exit;

            $res = mysqli_query($db->resourse(), $sql);
            $cou = mysqli_num_rows($res);
            if ($cou >= 1) {
                $row = mysqli_fetch_array($res);
                $_SESSION['client_user_id'] = $row[0];
                $_SESSION['client_user_id1'] = $row[0];
                $_SESSION['client_username'] = $row[1];
                $_SESSION['client_logged'] = true;
                // $_SESSION['adm_status']   = $row['status'];
                $r = "success";
            } else {
                $r = "fail";
            }
            echo $cou;
            // exit;
        }
    }
    echo $r;
}

/////login end/////////////////
?>

JQuery.min.js：4 POST 500（内部服务器错误）

0 个答案: