Question

我在下面找到了这个示例，用OKHttp发送HTTP POST消息。

我不明白如何将正文字符串传递给RequestBody。为什么需要两个参数？

RequestBody formBody = new FormBody.Builder()
                .add("message", "Your message")
                .build();
        Request request = new Request.Builder()
                .url("http://rhcloud.com")
                .post(formBody).addHeader("operation", "modifyRecords")
                .build();

        if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.KITKAT) {

            client.newCall(request).enqueue(new Callback() {
                @Override
                public void onFailure(Call call, IOException e) {
                    e.printStackTrace();
                }

                @Override
                public void onResponse(Call call, Response response) throws IOException {
                    try (ResponseBody responseBody = response.body()) {
                        if (!response.isSuccessful())
                            throw new IOException("Unexpected code " + response);

                        Headers responseHeaders = response.headers();
                        for (int i = 0, size = responseHeaders.size(); i < size; i++) {
                            System.out.println(responseHeaders.name(i) + ": " + responseHeaders.value(i));
                        }

                        System.out.println(responseBody.string());
                    }
                }
            });
        }
    }

Answer 1

我不确定我是否理解你的意思是正确的，但如果你问为什么FormBody .add（）有两个参数，那是因为它们是Key-Value-Pairs。第一个参数是名称，第二个参数是值。

无论如何，我认为this示例显示了如何发布字符串的更清晰的方法：

  public static final MediaType MEDIA_TYPE_MARKDOWN
      = MediaType.parse("text/x-markdown; charset=utf-8");

  private final OkHttpClient client = new OkHttpClient();

  public void run() throws Exception {
    String postBody = ""
        + "Releases\n"
        + "--------\n"
        + "\n"
        + " * _1.0_ May 6, 2013\n"
        + " * _1.1_ June 15, 2013\n"
        + " * _1.2_ August 11, 2013\n";

    Request request = new Request.Builder()
        .url("https://api.github.com/markdown/raw")
        .post(RequestBody.create(MEDIA_TYPE_MARKDOWN, postBody))
        .build();

    Response response = client.newCall(request).execute();
    if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);

    System.out.println(response.body().string());
  }

如何将正文传递给OKHttp消息？

1 个答案: