Question

请耐心等待，因为这是一个我正在努力解决的问题所以我可能不会很好地解释它！

我有一个值数组和两个字符串： e.g。

["5", "6"]
"DEPOT_NAME",
"DEPOT_ID"

我也有一个对象数组（在这个例子中只有一个但可以是多个）：

[
 {
  columns: [
   {name: "DEPOT_ID"}, 
   {name: "DEPOT_NAME"}, 
   {name; "REGION_ID"}, 
   {name: "CREATED_DATE"}, 
   {name: "MODIFIED_DATE"}
  ],
  id: 1,
  rows: [
   {data: {DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}
  ],
  title: "Depots"
 }
]

使用我拥有的值，我需要获取与DEPOT_NAME值对应的DEPOT_ID键的值。上面的数组可以用来找到我假设的正确的仓库ID，但是我怎样才能获得仓库名称的值？

我希望我解释说好的，如果你需要更多澄清，我会尽力让它更清楚。

非常感谢任何帮助。

感谢您的时间。

Answer 1

此示例生成一个包含元素“Bristol”和“Croydon”的数组（基于具有[5,6]的id数组）：

// your example object

var yourObj = [
 {
  columns: [
   {name: "DEPOT_ID"}, 
   {name: "DEPOT_NAME"}, 
   {name: "REGION_ID"}, 
   {name: "CREATED_DATE"}, 
   {name: "MODIFIED_DATE"}
  ],
  id: 1,
  rows: [
   {data: {DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
   {data: {DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}
  ],
  title: "Depots"
 }
];

// example code to fetch the depot names based on ids

var ids = [5, 6];
var depotNames = [];
for(var i = 0; i<yourObj.length; i++){
   var rows = yourObj[i].rows;
   for(var j =0; j < rows.length; j++){
     for(id in ids){
       if(rows[j].data.DEPOT_ID == ids[id]){
          depotNames.push(rows[j].data.DEPOT_NAME);
       }
     }

   }
}

Answer 2

您可以迭代对象并过滤所需的部分并仅获取目标值。

function getValues(key, values, target) {
    return data[0].rows.filter(function (a) {
        return values.indexOf(a.data[key]) !== -1;
    }).map(function (a) { return a.data[target]; });
}

var data = [{ columns: [{ name: "DEPOT_ID" }, { name: "DEPOT_NAME" }, { name: "REGION_ID" }, { name: "CREATED_DATE" }, { name: "MODIFIED_DATE" }], id: 1, rows: [{ data: { DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }], title: "Depots" }];

console.log(getValues("DEPOT_ID", ["5", "6"], "DEPOT_NAME"));

ES6

function getValues(key, values, target) {
    return data[0].rows.
        filter(a => values.indexOf(a.data[key]) !== -1).
        map(a => a.data[target]);
}

var data = [{ columns: [{ name: "DEPOT_ID" }, { name: "DEPOT_NAME" }, { name: "REGION_ID" }, { name: "CREATED_DATE" }, { name: "MODIFIED_DATE" }], id: 1, rows: [{ data: { DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }], title: "Depots" }];

console.log(getValues("DEPOT_ID", ["5", "6"], "DEPOT_NAME"));

Answer 3

function fetchData(cols, ids, mainArray) {
   var data = [];
   for(var i=0;i < mainArray.length; i++) {
      for(var c =0;c<mainArray[i].rows.length;c++) {

         for(var id in ids) {
            if(mainArray[i].rows[c].data.DEPOT_ID == ids[id]) {
               var temp = {};
               for(col in cols) {
                  temp[cols[col]] = mainArray[i].rows[c].data[cols[col]];
               }         
               data.push(temp);
            }
         }
      }
   }

   return data;
}

用法：fetchData（[＆＃34; DEPOT_NAME＆＃34;，＆＃34; DEPOT_ID＆＃34;]，[＆＃34; 5＆＃34;，＆＃34; 6＆＃34;]，YourArray）;

操纵数组和对象

3 个答案: