Question

当我在序列之后从启动器启动我的应用程序时：

SplashActivity.java

<activity
  android:name=".splash.SplashActivity"
  android:launchMode="singleTop"
  android:screenOrientation="portrait"
  android:theme="@style/SplashActivityTheme">
<intent-filter>
  <action android:name="android.intent.action.MAIN"/>

  <category android:name="android.intent.category.LAUNCHER"/>
</intent-filter>

HomeActivity.java

重现问题的步骤：

应用程序未在后台运行，也未处于暂停状态。
收到通知并显示在状态栏上。

用户点击通知并启动了HomeActivity.java。

FirebaseMessagingService.java

private void sendNotification(String messageBody, String title) {

    Intent intent = new Intent(this, HomeActivity.class);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
    PendingIntent pendingIntent =
        PendingIntent.getActivity(this, 0 /* Request code */, intent, PendingIntent.FLAG_ONE_SHOT);

    Uri defaultSoundUri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
    NotificationCompat.Builder notificationBuilder =
        new NotificationCompat.Builder(this).setSmallIcon(R.drawable.ic_stat_ic_notification)
            .setContentTitle(title)
            .setContentText(messageBody)
            .setAutoCancel(true)
            .setSound(defaultSoundUri)
            .setColor(ContextCompat.getColor(this, R.color.pantone_375))
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager =
        (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
    notificationManager.notify(++count /* ID of notification */, notificationBuilder.build());
}

保持HomeActivity.java打开并从启动器启动应用程序。启动相同应用程序的另一个实例，序列为SplashActivity.java - ＆gt; HomeActivity.java。

预期结果

应用程序的一个实例应存在于任何给定点。
如果应用程序已处于打开状态且用户在HomeActivity.java，则应该会收到焦点。
通过单击通知启动应用程序，应用程序处于打开状态。用户单击启动器图标，然后旧应用程序实例将获得焦点。

Answer 1

如果您在点击Activity时打开Notification，请打开以下Activity。即您的PendingIntent将在Activity

之后打开

请阅读以下comments中所写的所有Activity，以便了解为何已创建

public class NotificationHandlerActivity extends AppCompatActivity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        //deep linking - resuming app code
        if (isTaskRoot()) {
            // This Activity is the only Activity, so
            //  the app wasn't running. So start the app from the
            //  beginning (redirect to MainActivity)
        } else {
            // App was already running, so just finish, which will drop the user
            //  in to the activity that was at the top of the task stack
            Intent intent = getIntent();
            Uri data = intent.getData();
            //you can put your extra's if any
            finish();
        }
    }
}

Answer 2

据我了解，我想要开展每项活动的单一任务。如果我在这种情况下是正确的你必须使用android：launchMode =“singleInstance” 在activty AndroidManifest.xml文件中

或者查看本手册中的simular标志

https://developer.android.com/guide/topics/manifest/activity-element.html

电子。 G.

<activity android:name=". MainActivity" 
> 
>android:launchMode="singleInstance"label="@string/app_name">

Android：应用多个实例

2 个答案: